NaHCO₃ is the active ingredient in baking soda.How many grams of oxygen are present in 0.25 g of NaHCO₃? A)0.009 g B)0.048 g C)2.98 × 10³ g D)0.016 g E)0.14g

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Quizplus · Accepted Answer

The molecular formula for baking soda is NaHCO3. To find the grams of oxygen in 0.25 g of NaHCO3, first calculate the molar mass of NaHCO3: Na (22.99) + H (1.01) + C (12.01) + 3*O (3*16.00) = 84.01 g/mol. Oxygen's total mass in the compound is 3*16.00 = 48.00 g/mol. The fraction of the compound's mass that is oxygen is 48.00 / 84.01. To find the mass of oxygen in 0.25 g of NaHCO3, multiply this fraction by 0.25 g: (48.00 / 84.01) * 0.25 g ≈ 0.14 g.

NaHCO3 Is the Active Ingredient in Baking Soda

NaHCO₃ Is the Active Ingredient in Baking Soda