Analysis of a compound showed that it contained 76.0 % fluorine atoms and 24.0 % carbon atoms by mass.What is its empirical formula? A)CF₂ B)C₂F₃ C)CF₃ D)C₂F₅ E)CF

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Quizplus · Accepted Answer

The empirical formula is determined by the simplest whole number ratio of moles of each element. For fluorine (76.0% / 19.0 g/mol) and carbon (24.0% / 12.0 g/mol), the ratio simplifies to 2:1, giving CF₂.

Analysis of a Compound Showed That It Contained 76