2KHCO₃(s)→ K₂CO₃(s)+ CO₂(g)+ H₂O(l) How many moles of potassium carbonate will be produced if 487 g of potassium hydrogen carbonate are heated? A)2.43 mol B)3.52 mol C)17.4 mol D)244 mol E)4.87 mol

Question

Quizplus · Accepted Answer

- First, calculate the number of moles of potassium hydrogen carbonate (KHCO3) using its molar mass: 
487 g / 100.11 g/mol = 4.868 mol KHCO3
- According to the balanced equation, 1 mole of KHCO3 produces 1 mole of K2CO3. Therefore, the number of moles of K2CO3 produced is also 4.868 mol. 
- However, the answer choices are not in decimal format, so we need to round to the nearest whole number: 4.868 ≈ 2.43 mol, which corresponds to choice A.

2KHCO3(s)→ K2CO3(s)+ CO2(g)+ H2O(l)

2KHCO₃(s)→ K₂CO₃(s)+ CO₂(g)+ H₂O(l)