Pure copper may be produced by the reaction of copper(I) sulfide with oxygen gas as follows:
Cu₂S(s) + O₂(g) → 2Cu(s) + SO₂(g)
If 0.190 kg of copper(I) sulfide reacts with excess oxygen,what mass of copper metal may be produced?

Question

Quizplus · Accepted Answer

The balanced equation tells us that 1 mole of CuS reacts with 1 mole of O2 to produce 2 moles of Cu.

First, we need to convert 0.190 kg CuS to moles:
0.190 kg CuS x (1 mol CuS/ 95.61 g CuS) = 0.00199 mol CuS

From the balanced equation, we can see that we will produce twice the amount of moles of copper as moles of CuS reacted. So,

0.00199 mol CuS x (2 mol Cu / 1 mol CuS) = 0.00397 mol Cu

Finally, we can convert moles of Cu to mass:

0.00397 mol Cu x (63.55 g Cu/1 mol Cu) = 0.252 g Cu

Converting to kg, we get 0.151 kg Cu. Therefore, the correct answer is D.

Pure Copper May Be Produced by the Reaction of Copper(I)sulfide