A 24.5 mL aliquot of 0.0938 M H₂SO₄ (aq)is to be titrated with 0.0295 M NaOH (aq). What volume (mL)of base will it take to reach the equivalence point? A)156 B)0.136 C)77.9 D)39.0 E)4430

Question

Quizplus · Accepted Answer

The balanced equation is H2SO4 + 2NaOH → Na2SO4 + 2H2O. Moles of H2SO4 = 0.0245 L * 0.0938 M = 0.002299 mol. Since it reacts with 2 moles of NaOH, moles of NaOH needed = 0.002299 * 2 = 0.004598 mol. Volume of NaOH = 0.004598 mol / 0.0295 M = 0.156 L = 156 mL.

A 245 ML Aliquot of 0