What quantity of heat is required to change the temperature of 30.0 g of water at 10.0^°C to 25.0^°C? The specific heat of liquid water is 4.184 J/g^°C.

Question

Quizplus · Accepted Answer

The heat required can be calculated using the formula q = mcΔT. Here, m = 30.0 g, c = 4.184 J/g°C, and ΔT = 25.0°C - 10.0°C = 15.0°C. Thus, q = 30.0 g * 4.184 J/g°C * 15.0°C = 1882.8 J, which rounds to 1880 J.

What Quantity of Heat Is Required to Change the Temperature