Question 1

A proton is released such that it has an initial speed of 4.1 × 10⁵ m/s from left to right across the page.A magnetic field of 0.8 T is present at an angle of 45° to the horizontal direction (or positive x axis).What is the magnitude of the force experienced by the proton? (q_p = 1.6 × 10−¹⁹ C)

Accepted Answer

The magnitude of the force experienced by a charged particle moving through a magnetic field is given by:

F = qvBsinθ

Where q is the charge of the particle (in this case, a proton with a charge of +1.6 × 10−19 C), v is the velocity of the particle (4.1 × 10^5 m/s to the right), B is the magnetic field strength (0.8 T at an angle of 45° with the positive x axis), and θ is the angle between the particle's velocity and the magnetic field (45° in this case).

Plugging in the values, we get:

F = (1.6 × 10−19 C)(4.1 × 10^5 m/s)(0.8 T)sin(45°)
F = 3.7 × 10−14 N

Therefore, the correct answer is C.

Question 2

​An electron is accelerated from rest through 2300 V and then enters a region of uniform magnetic field with magnitude 1.25 T.What is the magnitude of the maximum magnetic force acting on the electron?

Accepted Answer

The maximum magnetic force on a charged particle is given by F = qvB, where q is the charge of the particle, v is its velocity, and B is the magnetic field strength. In this case, the electron has a charge of -1.602 x 10^-19 C, and its velocity is given by v = sqrt(2eV/m), where e is the electron's charge, V is the accelerating voltage, and m is the electron's mass. Plugging in the given values, we get v = 1.87 x 10^7 m/s. The magnetic field strength is given as 1.25 T. Plugging in these values, we get F = (-1.602 x 10^-19 C)(1.87 x 10^7 m/s)(1.25 T) = -4.07 x 10^-12 N. The negative sign indicates that the force is in the opposite direction of the electron's motion.

Question 3

The path of a charged particle moving parallel to a uniform magnetic field will be a

Accepted Answer

When a charged particle moves parallel to a uniform magnetic field, it experiences no magnetic force, thus it continues to move in a straight line.

Question 4

When a magnetic field causes a charged particle to move in a circular path,the only quantity listed below which the magnetic force changes significantly as the particle goes around in a circle is the particle's:

Accepted Answer

The magnetic force exerted on a charged particle moving in a magnetic field is given by F = q(v x B), where v is the velocity of the particle and B is the magnetic field. This force is perpendicular to both the velocity and the magnetic field, and thus it causes the charged particle to move in a circular path. 
The radius of the circular path depends on the velocity, mass, and charge of the particle, as well as the strength of the magnetic field. However, the momentum of the particle (p=mv) is conserved in the absence of external forces, and thus it remains constant as the particle moves in a circle. Therefore, the magnetic force does not change the momentum of the particle significantly as it goes around in a circle.

Question 5

A proton and a deuteron are moving with equal velocities perpendicular to a uniform magnetic field.A deuteron has the same charge as the proton but has twice its mass.The ratio of the acceleration of the proton to that of the deuteron is:

Accepted Answer

The acceleration $a$ of a charged particle in a magnetic field is given by $a = \frac{F}{m}$, where $F = qvB$ is the magnetic force, $q$ is the charge, $v$ is the velocity, $B$ is the magnetic field strength, and $m$ is the mass of the particle. Since both the proton and the deuteron have the same charge and are moving with the same velocity in the magnetic field, the force $F$ on both particles is the same. However, the deuteron has twice the mass of the proton ($m_{deuteron} = 2m_{proton}$). Therefore, the acceleration of the proton is twice that of the deuteron, making the ratio of the acceleration of the proton to that of the deuteron $2:1$ or simply $2$.

Question 6

A proton moving with a speed of 3.20 × 10⁵ m/s perpendicular to a uniform magnetic field of 0.0786 T will follow which of the paths described below? (q_p = 1.60 × 10−¹⁹ C and m_p = 1.67 × 10−²⁷ kg)

Accepted Answer

The path of a charged particle moving perpendicular to a uniform magnetic field is circular. The radius of the path can be calculated using the formula $r = \frac{mv}{qB}$, where $m$ is the mass of the particle, $v$ is its velocity, $q$ is its charge, and $B$ is the magnetic field strength. Substituting the given values ($m = 1.67 \times 10^{-27}$ kg, $v = 3.20 \times 10^{7}$ m/s, $q = 1.60 \times 10^{-19}$ C, $B = 0.0786$ T) into the formula gives a radius of approximately 4.25 cm, which corresponds to choice B.

Question 7

A proton is released such that its initial velocity is from right to left across this page.The proton's path,however,is deflected in a direction toward the bottom edge of the page due to the presence of a uniform magnetic field.What is the direction of this field?

Accepted Answer

According to the right-hand rule, if a charged particle is moving in a certain direction and it experiences a force perpendicular to both its velocity and the magnetic field, the magnetic field must be directed into the page. In this case, the proton's velocity is from right to left across the page, and its path is deflected towards the bottom edge of the page, so the magnetic field must be directed into the page. Thus, the correct answer is B.

Question 8

A proton moving at a speed of 4.2 × 10⁶ m/s cuts across the lines of a magnetic field at an angle of 78°.The strength of the field is 0.91 × 10−⁴ T.What is the magnitude of the force acting on the proton? (q_p = 1.6 × 10−¹⁹ C)

Accepted Answer

The answer of A proton moving at a speed of...

Question 9

Two singly ionized isotopes,X and Y,of the same element move with the same speed perpendicular to a uniform magnetic field.Isotope X follows a path of radius 3.37 cm while isotope Y moves along a path 3.58 cm in radius.What is the ratio of the two isotope masses, 
?

Accepted Answer

The answer of Two singly ionized isotopes,X and Y,of the...

Question 10

A proton,mass 1.67 × 10−²⁷ kg and charge +1.6 × 10−¹⁹ C,moves in a circular orbit perpendicular to a uniform magnetic field of 0.86 T.Find the time for the proton to make one complete circular orbit.

Accepted Answer

The answer of A proton,mass 1.67 × 10−²⁷ kg and...

Question 11

If a charged particle is moving in a uniform magnetic field,its path can be

Accepted Answer

The path of a charged particle moving in a uniform magnetic field can be a straight line (if it moves parallel to the field lines), a circle (if it moves perpendicular to the field lines), or a helix (if it moves at an angle to the field lines).

Question 12

A proton and a deuteron are moving with equal velocities perpendicular to a uniform magnetic field.A deuteron has the same charge as the proton but has twice its mass.The ratio of the magnetic force on the proton to that on the deuteron is:

Accepted Answer

The magnetic force acting on a charged particle moving with a velocity perpendicular to a uniform magnetic field is given by F=qvB, where q is the charge, v is the velocity and B is the magnetic field. Since both the proton and deuteron are moving with equal velocities, the only difference in the magnetic force acting on them is due to their charges and masses. As the charges are the same, the ratio of magnetic forces will be proportional to the ratio of their masses. Therefore, the ratio of the magnetic force on the proton to that on the deuteron is given by (mp/mD)=0.5/1=0.5, where mp and mD are the masses of the proton and deuteron, respectively. Therefore, the answer is B.

Question 13

An electron moves through a region of crossed electric and magnetic fields.The electric field E = 2 300 V/m and is directed straight down.The magnetic field B = 0.95 T and is directed to the left.For what velocity v of the electron into the paper will the electric force exactly cancel the magnetic force?

Accepted Answer

When the electric force is equal and opposite to the magnetic force experienced by the electron, we have:
qE = qvB
where q is the charge of the electron, E is the electric field, v is the velocity of the electron, and B is the magnetic field.
Solving for v, we get:
v = E/B
Substituting the given values, we have:
v = 2 300/0.95 = 2 421.05 m/s
Therefore, the velocity at which the electric force exactly cancels the magnetic force is around 2 421.05 m/s, which is closest to option A) 2 400 m/s.

Question 14

A proton moves through a magnetic field of magnitude 1.40 T with speed 5.00 *10⁶m/s.What is the magnitude of the maximum acceleration of the proton? The mass of a proton is 1.67 *10^-27 kg,and its charge is 1.6 *10^-19 C.

Accepted Answer

The maximum acceleration of a charged particle moving through a magnetic field is given by
a = (q/m)Bv
where q is the charge of the particle, m is its mass, B is the magnetic field strength, and v is its velocity.
Substituting the given values, we get
a = (1.6E-19 C / 1.67E-27 kg) * 1.40 T * 5.00E6 m/s
a = 6.71E14 m/s^2
Therefore, the magnitude of the maximum acceleration of the proton is 6.71E14 m/s^2. The correct answer is B.

Question 15

A proton,which moves perpendicular to a magnetic field of 1.4 T in a circular path of radius 0.074 m,has what speed? (q_p = 1.60 × 10−¹⁹ C and m_p = 1.67 × 10−²⁷ kg)

Accepted Answer

The answer of A proton,which moves perpendicular to a magnetic...

Question 16

At the Fermilab accelerator in Weston,Illinois,singly-charged ions with momentum 3.3 × 10−¹⁶ kg⋅m/s are held in a circular orbit of radius 1.00 km by an upward magnetic field.What B field must be used to maintain the ions in this orbit? (qion = 1.60 × 10−¹⁹ C)

Accepted Answer

The answer of At the Fermilab accelerator in Weston,Illinois,singly-charged ions...

Question 17

A proton is circling the Earth above the magnetic equator,where Earth's magnetic field is directed horizontally north and has a magnitude of 4.00 × 10^-8 T.If the proton is moving at a speed of 2.7 × 10⁷ m/s,how far above the surface of the Earth is the proton? Earth's radius is 6.38 × 10⁶ m,a proton's mass is 1.67 × 10^-27 kg,and its charge is 1.6 × 10^-19 C.

Accepted Answer

The answer of ​A proton is circling the Earth above...

Question 18

The magnetic field of the Earth at a particular location is directed vertically downward with magnitude of 40.0 μT.An electron is moving horizontally toward the west in this field with a speed of 5.2 × 10⁶ m/s.What are the direction and magnitude of the magnetic force the field exerts on the electron? (e = 1.6 × 10^-19 C)

Accepted Answer

The magnitude of the magnetic force can be calculated using the formula $F = qvB\sin(\theta)$, where $q$ is the charge of the electron ($1.6 \times 10^{-19} C$), $v$ is the velocity of the electron ($5.2 \times 10^6 m/s$), $B$ is the magnetic field ($40.0 \mu T = 40.0 \times 10^{-6} T$), and $\theta$ is the angle between the velocity of the electron and the magnetic field, which is $90^\circ$ since the electron is moving horizontally and the field is vertical. Thus, $\sin(\theta) = \sin(90^\circ) = 1$.Substituting the values, we get:$$F = (1.6 \times 10^{-19} C) \times (5.2 \times 10^6 m/s) \times (40.0 \times 10^{-6} T) \times 1 = 3.328 \times 10^{-17} N$$The direction of the magnetic force can be determined using the right-hand rule. Since the electron is negatively charged and moving toward the west in a downward magnetic field, the force will be directed to the north.

Question 19

A deuteron,with the same charge but twice the mass of a proton,moves with a speed of 6.00 × 10⁵ m/s perpendicular to a uniform magnetic field of 0.0525 T.Which of the paths described below would it follow? (q_p = 1.60 × 10−¹⁹ C and m_d = 3.34 × 10−²⁷ kg)

Accepted Answer

The path that the deuteron follows is given by:

r = mv/qB

where r is the radius of the circular path, v is the velocity of the deuteron, q is its charge, m is its mass, and B is the magnetic field strength.

Plugging in the given values, we get:

r = (2*3.34x10^-27 kg)(6.00x10^5 m/s)/(1.6x10^-19 C)(0.0525 T)
r ≈ 0.0239 m = 23.9 cm

Therefore, the deuteron would follow circular path with a radius of 23.9 cm. Choice C is the correct answer.

Question 20

In a mass spectrometer,an ion will have a smaller radius for its circular path if

Accepted Answer

A greater charge increases the magnetic force on the ion, reducing the radius of its circular path.

Quiz 19: Magnetism

An electron is accelerated from rest through 2300 V and then enters a region of uniform magnetic field with magnitude 1.25 T.What is the magnitude of the maximum magnetic force acting on the electron?

The path of a charged particle moving parallel to a uniform magnetic field will be a

When a magnetic field causes a charged particle to move in a circular path,the only quantity listed below which the magnetic force changes significantly as the particle goes around in a circle is the particle's:

A proton and a deuteron are moving with equal velocities perpendicular to a uniform magnetic field.A deuteron has the same charge as the proton but has twice its mass.The ratio of the acceleration of the proton to that of the deuteron is:

A proton moving with a speed of 3.20 × 10⁵ m/s perpendicular to a uniform magnetic field of 0.0786 T will follow which of the paths described below? (q_p = 1.60 × 10−¹⁹ C and m_p = 1.67 × 10−²⁷ kg)

A proton is released such that its initial velocity is from right to left across this page.The proton's path,however,is deflected in a direction toward the bottom edge of the page due to the presence of a uniform magnetic field.What is the direction of this field?

A proton moving at a speed of 4.2 × 10⁶ m/s cuts across the lines of a magnetic field at an angle of 78°.The strength of the field is 0.91 × 10−⁴ T.What is the magnitude of the force acting on the proton? (q_p = 1.6 × 10−¹⁹ C)

Two singly ionized isotopes,X and Y,of the same element move with the same speed perpendicular to a uniform magnetic field.Isotope X follows a path of radius 3.37 cm while isotope Y moves along a path 3.58 cm in radius.What is the ratio of the two isotope masses, ?

A proton,mass 1.67 × 10−²⁷ kg and charge +1.6 × 10−¹⁹ C,moves in a circular orbit perpendicular to a uniform magnetic field of 0.86 T.Find the time for the proton to make one complete circular orbit.

If a charged particle is moving in a uniform magnetic field,its path can be

A proton and a deuteron are moving with equal velocities perpendicular to a uniform magnetic field.A deuteron has the same charge as the proton but has twice its mass.The ratio of the magnetic force on the proton to that on the deuteron is:

A proton moves through a magnetic field of magnitude 1.40 T with speed 5.00 10⁶m/s.What is the magnitude of the maximum acceleration of the proton? The mass of a proton is 1.67 10^-27 kg,and its charge is 1.6 *10^-19 C.

A proton,which moves perpendicular to a magnetic field of 1.4 T in a circular path of radius 0.074 m,has what speed? (q_p = 1.60 × 10−¹⁹ C and m_p = 1.67 × 10−²⁷ kg)

At the Fermilab accelerator in Weston,Illinois,singly-charged ions with momentum 3.3 × 10−¹⁶ kg⋅m/s are held in a circular orbit of radius 1.00 km by an upward magnetic field.What B field must be used to maintain the ions in this orbit? (qion = 1.60 × 10−¹⁹ C)

A deuteron,with the same charge but twice the mass of a proton,moves with a speed of 6.00 × 10⁵ m/s perpendicular to a uniform magnetic field of 0.0525 T.Which of the paths described below would it follow? (q_p = 1.60 × 10−¹⁹ C and m_d = 3.34 × 10−²⁷ kg)

In a mass spectrometer,an ion will have a smaller radius for its circular path if

Quiz 19: Magnetism

​An electron is accelerated from rest through 2300 V and then enters a region of uniform magnetic field with magnitude 1.25 T.What is the magnitude of the maximum magnetic force acting on the electron?

The path of a charged particle moving parallel to a uniform magnetic field will be a

When a magnetic field causes a charged particle to move in a circular path,the only quantity listed below which the magnetic force changes significantly as the particle goes around in a circle is the particle's:

A proton and a deuteron are moving with equal velocities perpendicular to a uniform magnetic field.A deuteron has the same charge as the proton but has twice its mass.The ratio of the acceleration of the proton to that of the deuteron is:

A proton moving with a speed of 3.20 × 105 m/s perpendicular to a uniform magnetic field of 0.0786 T will follow which of the paths described below? (qp = 1.60 × 10−19 C and mp = 1.67 × 10−27 kg)

A proton is released such that its initial velocity is from right to left across this page.The proton's path,however,is deflected in a direction toward the bottom edge of the page due to the presence of a uniform magnetic field.What is the direction of this field?

A proton moving at a speed of 4.2 × 106 m/s cuts across the lines of a magnetic field at an angle of 78°.The strength of the field is 0.91 × 10−4 T.What is the magnitude of the force acting on the proton? (qp = 1.6 × 10−19 C)

Two singly ionized isotopes,X and Y,of the same element move with the same speed perpendicular to a uniform magnetic field.Isotope X follows a path of radius 3.37 cm while isotope Y moves along a path 3.58 cm in radius.What is the ratio of the two isotope masses, ?

A proton,mass 1.67 × 10−27 kg and charge +1.6 × 10−19 C,moves in a circular orbit perpendicular to a uniform magnetic field of 0.86 T.Find the time for the proton to make one complete circular orbit.

If a charged particle is moving in a uniform magnetic field,its path can be

A proton and a deuteron are moving with equal velocities perpendicular to a uniform magnetic field.A deuteron has the same charge as the proton but has twice its mass.The ratio of the magnetic force on the proton to that on the deuteron is:

A proton moves through a magnetic field of magnitude 1.40 T with speed 5.00 *106 m/s.What is the magnitude of the maximum acceleration of the proton? The mass of a proton is 1.67 *10-27 kg,and its charge is 1.6 *10-19 C.

A proton,which moves perpendicular to a magnetic field of 1.4 T in a circular path of radius 0.074 m,has what speed? (qp = 1.60 × 10−19 C and mp = 1.67 × 10−27 kg)

At the Fermilab accelerator in Weston,Illinois,singly-charged ions with momentum 3.3 × 10−16 kg⋅m/s are held in a circular orbit of radius 1.00 km by an upward magnetic field.What B field must be used to maintain the ions in this orbit? (qion = 1.60 × 10−19 C)

A deuteron,with the same charge but twice the mass of a proton,moves with a speed of 6.00 × 105 m/s perpendicular to a uniform magnetic field of 0.0525 T.Which of the paths described below would it follow? (qp = 1.60 × 10−19 C and md = 3.34 × 10−27 kg)

In a mass spectrometer,an ion will have a smaller radius for its circular path if

An electron is accelerated from rest through 2300 V and then enters a region of uniform magnetic field with magnitude 1.25 T.What is the magnitude of the maximum magnetic force acting on the electron?

A proton moving with a speed of 3.20 × 10⁵ m/s perpendicular to a uniform magnetic field of 0.0786 T will follow which of the paths described below? (q_p = 1.60 × 10−¹⁹ C and m_p = 1.67 × 10−²⁷ kg)

A proton moving at a speed of 4.2 × 10⁶ m/s cuts across the lines of a magnetic field at an angle of 78°.The strength of the field is 0.91 × 10−⁴ T.What is the magnitude of the force acting on the proton? (q_p = 1.6 × 10−¹⁹ C)

A proton,mass 1.67 × 10−²⁷ kg and charge +1.6 × 10−¹⁹ C,moves in a circular orbit perpendicular to a uniform magnetic field of 0.86 T.Find the time for the proton to make one complete circular orbit.

A proton moves through a magnetic field of magnitude 1.40 T with speed 5.00 10⁶m/s.What is the magnitude of the maximum acceleration of the proton? The mass of a proton is 1.67 10^-27 kg,and its charge is 1.6 *10^-19 C.

A proton,which moves perpendicular to a magnetic field of 1.4 T in a circular path of radius 0.074 m,has what speed? (q_p = 1.60 × 10−¹⁹ C and m_p = 1.67 × 10−²⁷ kg)

At the Fermilab accelerator in Weston,Illinois,singly-charged ions with momentum 3.3 × 10−¹⁶ kg⋅m/s are held in a circular orbit of radius 1.00 km by an upward magnetic field.What B field must be used to maintain the ions in this orbit? (qion = 1.60 × 10−¹⁹ C)

A deuteron,with the same charge but twice the mass of a proton,moves with a speed of 6.00 × 10⁵ m/s perpendicular to a uniform magnetic field of 0.0525 T.Which of the paths described below would it follow? (q_p = 1.60 × 10−¹⁹ C and m_d = 3.34 × 10−²⁷ kg)