Question 1

Telephone survey
A political telephone survey of 360 people asked whether they were in favor or not in favor of a proposed law.Each person was identified as either Republican or Democrat.The results are shown in the following table:
 $$\begin{array} { | l | c | c | c | c | } 
\hline \text { Party } & \text { In Favar } & \text { Nat in Favar } & \text { Undecided } & \text { Tatal } \
\hline \text { Republican } & 98 & 54 & 4 \square & 192 \
\hline \text { Democrat } & 79 & 29 & 60 & 168 \
\hline \text { Tatal } & 177 & 83 & 100 & 360 \
\hline
\end{array}$$
-What is the probability that a randomly selected respondent was a Democrat?

Accepted Answer

The answer of Telephone survey
A political telephone survey of 360...

Question 2

Telephone survey
A political telephone survey of 360 people asked whether they were in favor or not in favor of a proposed law.Each person was identified as either Republican or Democrat.The results are shown in the following table:
 $$\begin{array} { | l | c | c | c | c | } 
\hline \text { Party } & \text { In Favar } & \text { Nat in Favar } & \text { Undecided } & \text { Tatal } \
\hline \text { Republican } & 98 & 54 & 4 \square & 192 \
\hline \text { Democrat } & 79 & 29 & 60 & 168 \
\hline \text { Tatal } & 177 & 83 & 100 & 360 \
\hline
\end{array}$$
-What is the probability that a randomly selected respondent was a Democrat or not in favor of the proposed law?

Accepted Answer

The answer of Telephone survey
A political telephone survey of 360...

Question 3

Event $$\begin{array}{l}
\quad \quad \quad \quad \quad \quad \quad \quad \text { Event }\
\begin{array} { | c | c c c c | c | } 
\hline \text { Event } & \boldsymbol { C 1 } & \mathbf { C 2 } & \mathbf { C 3 } & \mathbf { C 4 } & \text { Total } \
\hline \text { DI } & 75 & 125 & 65 & 35 & 300 \
\text { D2 } & 90 & 105 & 60 & 45 & 300 \
\text { D3 } & 135 & 120 & 75 & 70 & 400 \
\hline \text { Total: } & 300 & 325 & 200 & 150 & 1000 \
\hline
\end{array}
\end{array}$$
-Find P (D1)or P (C1).

Accepted Answer

The answer of Event \[\begin{array}{l}
\quad \quad \quad \quad \quad \quad...

Question 4

Candidate
Six candidates for a new position of vice-president for academic affairs have been selected.Three of the candidates are female.The candidates' years of experience are as follows: $$\begin{array} { | c | c | } 
\hline \text { Candidate } & \text { Experience } \
\hline \text { Female 1 } & 5 \
\text { Female 2 } & 9 \
\text { Female 3 } & 11 \
\text { Male 1 } & 6 \
\text { Male 2 } & 4 \
\text { Male 3 } & 8 \
\hline
\end{array}$$ Suppose one of the candidates is selected at random.Define the following events:
A = person selected has 9 years experience.
B = person selected is a female.
-Find P(A).

Accepted Answer

The answer of Candidate
Six candidates for a new position of...

Question 5

Manufacturers
A large men's store in a mall purchases suits from four different manufacturers in short,regular,and long.Their current selections are given in the contingency table below: $$\begin{array}{l}
\quad \quad \quad \quad \quad \quad \quad \text { Маnufacturers }\
\begin{array} { | c | c c c c | c | } 
\hline \text { Length } & \boldsymbol { H M S } & \boldsymbol { H F } & \boldsymbol { R L } & \boldsymbol { J C } & \text { Total } \
\hline S & 15 & 15 & 35 & 35 & 100 \
R & 60 & 70 & 75 & 70 & 275 \
L & 25 & 35 & 40 & 25 & 125 \
\hline \text { Total: } & 100 & 120 & 150 & 130 & 500 \
\hline
\end{array}
\end{array}$$ Let the abbreviations and letters represent the events.For example Event S = a randomly selected suit is short,event HMS = a randomly selected suit is manufactured by HMS.
-Compute P(S).

Accepted Answer

The answer of Manufacturers
A large men's store in a mall...

Question 6

Odds
The odds in favor of an event are the number of successes divided by the number of failures.The probability of this event occurring is the number of successes divided by the sum of the number of successes and the number of failures.The number of successes is five and the number of failures is four.
Find the probability of failure.

Accepted Answer

The answer of Odds
The odds in favor of an event...

Question 7

Event $$\begin{array}{l}
\quad \quad \quad \quad \quad \quad \quad \quad \text { Event }\
\begin{array} { | c | c c c c | c | } 
\hline \text { Event } & \boldsymbol { C 1 } & \mathbf { C 2 } & \mathbf { C 3 } & \mathbf { C 4 } & \text { Total } \
\hline \text { DI } & 75 & 125 & 65 & 35 & 300 \
\text { D2 } & 90 & 105 & 60 & 45 & 300 \
\text { D3 } & 135 & 120 & 75 & 70 & 400 \
\hline \text { Total: } & 300 & 325 & 200 & 150 & 1000 \
\hline
\end{array}
\end{array}$$
-Find P (D1 or D2 or D3).

Accepted Answer

The answer of Event \[\begin{array}{l}
\quad \quad \quad \quad \quad \quad...

Question 8

Manufacturers
A large men's store in a mall purchases suits from four different manufacturers in short,regular,and long.Their current selections are given in the contingency table below: $$\begin{array}{l}
\quad \quad \quad \quad \quad \quad \quad \text { Маnufacturers }\
\begin{array} { | c | c c c c | c | } 
\hline \text { Length } & \boldsymbol { H M S } & \boldsymbol { H F } & \boldsymbol { R L } & \boldsymbol { J C } & \text { Total } \
\hline S & 15 & 15 & 35 & 35 & 100 \
R & 60 & 70 & 75 & 70 & 275 \
L & 25 & 35 & 40 & 25 & 125 \
\hline \text { Total: } & 100 & 120 & 150 & 130 & 500 \
\hline
\end{array}
\end{array}$$ Let the abbreviations and letters represent the events.For example Event S = a randomly selected suit is short,event HMS = a randomly selected suit is manufactured by HMS.
-Compute P(HMS / S).

Accepted Answer

The answer of Manufacturers
A large men's store in a mall...

Question 9

Candidate
Six candidates for a new position of vice-president for academic affairs have been selected.Three of the candidates are female.The candidates' years of experience are as follows: $$\begin{array} { | c | c | } 
\hline \text { Candidate } & \text { Experience } \
\hline \text { Female 1 } & 5 \
\text { Female 2 } & 9 \
\text { Female 3 } & 11 \
\text { Male 1 } & 6 \
\text { Male 2 } & 4 \
\text { Male 3 } & 8 \
\hline
\end{array}$$ Suppose one of the candidates is selected at random.Define the following events:
A = person selected has 9 years experience.
B = person selected is a female.
-Find P(B).

Accepted Answer

The answer of Candidate
Six candidates for a new position of...

Question 10

Event $$\begin{array}{l}
\quad \quad \quad \quad \quad \quad \quad \quad \text { Event }\
\begin{array} { | c | c c c c | c | } 
\hline \text { Event } & \boldsymbol { C 1 } & \mathbf { C 2 } & \mathbf { C 3 } & \mathbf { C 4 } & \text { Total } \
\hline \text { DI } & 75 & 125 & 65 & 35 & 300 \
\text { D2 } & 90 & 105 & 60 & 45 & 300 \
\text { D3 } & 135 & 120 & 75 & 70 & 400 \
\hline \text { Total: } & 300 & 325 & 200 & 150 & 1000 \
\hline
\end{array}
\end{array}$$
-Find P (C1 and D1).

Accepted Answer

The answer of Event \[\begin{array}{l}
\quad \quad \quad \quad \quad \quad...

Question 11

Manufacturers
A large men's store in a mall purchases suits from four different manufacturers in short,regular,and long.Their current selections are given in the contingency table below: $$\begin{array}{l}
\quad \quad \quad \quad \quad \quad \quad \text { Маnufacturers }\
\begin{array} { | c | c c c c | c | } 
\hline \text { Length } & \boldsymbol { H M S } & \boldsymbol { H F } & \boldsymbol { R L } & \boldsymbol { J C } & \text { Total } \
\hline S & 15 & 15 & 35 & 35 & 100 \
R & 60 & 70 & 75 & 70 & 275 \
L & 25 & 35 & 40 & 25 & 125 \
\hline \text { Total: } & 100 & 120 & 150 & 130 & 500 \
\hline
\end{array}
\end{array}$$ Let the abbreviations and letters represent the events.For example Event S = a randomly selected suit is short,event HMS = a randomly selected suit is manufactured by HMS.
-Compute P(HMS).

Accepted Answer

The answer of Manufacturers
A large men's store in a mall...

Question 12

Telephone survey
A political telephone survey of 360 people asked whether they were in favor or not in favor of a proposed law.Each person was identified as either Republican or Democrat.The results are shown in the following table:
 $$\begin{array} { | l | c | c | c | c | } 
\hline \text { Party } & \text { In Favar } & \text { Nat in Favar } & \text { Undecided } & \text { Tatal } \
\hline \text { Republican } & 98 & 54 & 4 \square & 192 \
\hline \text { Democrat } & 79 & 29 & 60 & 168 \
\hline \text { Tatal } & 177 & 83 & 100 & 360 \
\hline
\end{array}$$
-What is the probability that a randomly selected respondent was a Republican and undecided about the proposed law?

Accepted Answer

The answer of Telephone survey
A political telephone survey of 360...

Question 13

In the board game called TRIVIAL PURSUIT,a single die is used to determine the number of spaces a player is allowed to move.A player is currently positioned 3 spaces from a space where a correct answer will earn a "pie" and 4 spaces from a space where "roll again" is the option.Assuming a fair die,what is the probability the player will get to answer a question for a "pie" or get to "roll again"?

Accepted Answer

The answer of In the board game called TRIVIAL PURSUIT,a...

Question 14

Candidate
Six candidates for a new position of vice-president for academic affairs have been selected.Three of the candidates are female.The candidates' years of experience are as follows: $$\begin{array} { | c | c | } 
\hline \text { Candidate } & \text { Experience } \
\hline \text { Female 1 } & 5 \
\text { Female 2 } & 9 \
\text { Female 3 } & 11 \
\text { Male 1 } & 6 \
\text { Male 2 } & 4 \
\text { Male 3 } & 8 \
\hline
\end{array}$$ Suppose one of the candidates is selected at random.Define the following events:
A = person selected has 9 years experience.
B = person selected is a female.
-Find P(not A / B).

Accepted Answer

The answer of Candidate
Six candidates for a new position of...

Question 15

Candidate
Six candidates for a new position of vice-president for academic affairs have been selected.Three of the candidates are female.The candidates' years of experience are as follows: $$\begin{array} { | c | c | } 
\hline \text { Candidate } & \text { Experience } \
\hline \text { Female 1 } & 5 \
\text { Female 2 } & 9 \
\text { Female 3 } & 11 \
\text { Male 1 } & 6 \
\text { Male 2 } & 4 \
\text { Male 3 } & 8 \
\hline
\end{array}$$ Suppose one of the candidates is selected at random.Define the following events:
A = person selected has 9 years experience.
B = person selected is a female.
-Find P(A / B).

Accepted Answer

The answer of Candidate
Six candidates for a new position of...

Question 16

Manufacturers
A large men's store in a mall purchases suits from four different manufacturers in short,regular,and long.Their current selections are given in the contingency table below: $$\begin{array}{l}
\quad \quad \quad \quad \quad \quad \quad \text { Маnufacturers }\
\begin{array} { | c | c c c c | c | } 
\hline \text { Length } & \boldsymbol { H M S } & \boldsymbol { H F } & \boldsymbol { R L } & \boldsymbol { J C } & \text { Total } \
\hline S & 15 & 15 & 35 & 35 & 100 \
R & 60 & 70 & 75 & 70 & 275 \
L & 25 & 35 & 40 & 25 & 125 \
\hline \text { Total: } & 100 & 120 & 150 & 130 & 500 \
\hline
\end{array}
\end{array}$$ Let the abbreviations and letters represent the events.For example Event S = a randomly selected suit is short,event HMS = a randomly selected suit is manufactured by HMS.
-Compute P(S /HMS).

Accepted Answer

The answer of Manufacturers
A large men's store in a mall...

Question 17

Manufacturers
A large men's store in a mall purchases suits from four different manufacturers in short,regular,and long.Their current selections are given in the contingency table below: $$\begin{array}{l}
\quad \quad \quad \quad \quad \quad \quad \text { Маnufacturers }\
\begin{array} { | c | c c c c | c | } 
\hline \text { Length } & \boldsymbol { H M S } & \boldsymbol { H F } & \boldsymbol { R L } & \boldsymbol { J C } & \text { Total } \
\hline S & 15 & 15 & 35 & 35 & 100 \
R & 60 & 70 & 75 & 70 & 275 \
L & 25 & 35 & 40 & 25 & 125 \
\hline \text { Total: } & 100 & 120 & 150 & 130 & 500 \
\hline
\end{array}
\end{array}$$ Let the abbreviations and letters represent the events.For example Event S = a randomly selected suit is short,event HMS = a randomly selected suit is manufactured by HMS.
-Compute P(S and HMS).

Accepted Answer

The answer of Manufacturers
A large men's store in a mall...

Question 18

Event $$\begin{array}{l}
\quad \quad \quad \quad \quad \quad \quad \quad \text { Event }\
\begin{array} { | c | c c c c | c | } 
\hline \text { Event } & \boldsymbol { C 1 } & \mathbf { C 2 } & \mathbf { C 3 } & \mathbf { C 4 } & \text { Total } \
\hline \text { DI } & 75 & 125 & 65 & 35 & 300 \
\text { D2 } & 90 & 105 & 60 & 45 & 300 \
\text { D3 } & 135 & 120 & 75 & 70 & 400 \
\hline \text { Total: } & 300 & 325 & 200 & 150 & 1000 \
\hline
\end{array}
\end{array}$$
-Find P (C1 or D1).

Accepted Answer

The answer of Event \[\begin{array}{l}
\quad \quad \quad \quad \quad \quad...

Question 19

Shoe store
A shoe store carries 590 pairs of Stacy-Adams and 610 pairs of Freeman brands of shoes.Let a success be the event of randomly selecting a pair of Stacy-Adams shoes.
Find the probability of a success.

Accepted Answer

The answer of Shoe store
A shoe store carries 590 pairs...

Question 20

Telephone survey
A political telephone survey of 360 people asked whether they were in favor or not in favor of a proposed law.Each person was identified as either Republican or Democrat.The results are shown in the following table:
 $$\begin{array} { | l | c | c | c | c | } 
\hline \text { Party } & \text { In Favar } & \text { Nat in Favar } & \text { Undecided } & \text { Tatal } \
\hline \text { Republican } & 98 & 54 & 4 \square & 192 \
\hline \text { Democrat } & 79 & 29 & 60 & 168 \
\hline \text { Tatal } & 177 & 83 & 100 & 360 \
\hline
\end{array}$$
-What is the probability that a randomly selected respondent was in favor of the proposed law?

Accepted Answer

The answer of Telephone survey
A political telephone survey of 360...

Quiz 5: Probability: Review of Basic Concepts

Shoe store A shoe store carries 590 pairs of Stacy-Adams and 610 pairs of Freeman brands of shoes.Let a success be the event of randomly selecting a pair of Stacy-Adams shoes. Find the probability of a success.