Potassium hydrogen carbonate decomposes with heat as follows:
2KHCO₃(s) $\to$ K₂CO₃(s) + CO₂(g) + H₂O(l)
How many moles of potassium carbonate will be produced if 201 g of potassium hydrogen carbonate are heated?

Question

Potassium hydrogen carbonate decomposes with heat as follows:
2KHCO₃(s)

\to

K₂CO₃(s) + CO₂(g) + H₂O(l)
How many moles of potassium carbonate will be produced if 201 g of potassium hydrogen carbonate are heated?

Quizplus · Accepted Answer

The molar mass of KHCO₃ is approximately 100.11 g/mol. Therefore, 201 g of KHCO₃ is about 2.01 moles. According to the balanced equation, 2 moles of KHCO₃ produce 1 mole of K₂CO₃. Thus, 2.01 moles of KHCO₃ will produce approximately 1.00 mole of K₂CO₃.

Potassium Hydrogen Carbonate Decomposes with Heat as Follows: 2KHCO3(s) →\to→ K2CO3(s)+ CO2(g)+ H2O(l) How Many Moles of Potassium Carbonate Will

Potassium Hydrogen Carbonate Decomposes with Heat as Follows:
2KHCO₃(s) $\to$ K₂CO₃(s)+ CO₂(g)+ H₂O(l)
How Many Moles of Potassium Carbonate Will