Evaluate the indefinite integral as a power series. $\int \tan ^ { - 1 } \left( t ^ { 2 } \right) d t$
A) $C + \sum _ { n = 0 } ^ { \infty } \frac { ( - 1 ) ^ { n } t ^ { 2 n + 3 } } { ( 2 n + 3 ) }$
B) $C + \sum _ { n = 0 } ^ { \infty } \frac { ( - 1 ) ^ { n } t ^ { 4 n + 3 } } { ( 2 n + 1 ) ( 4 n + 3 ) }$
C) $C + \sum _ { n = 0 } ^ { \infty } \frac { ( - 1 ) ^ { n } t ^ { 2 n + 2 } } { ( 2 n + 1 ) }$
D) $C + \sum _ { n = 0 } ^ { \infty } \frac { ( - 1 ) ^ { n } t ^ { 4 n + 2 } } { ( 2 n + 1 ) ( 4 n + 3 ) }$
E) $C + \sum _ { n = 0 } ^ { \infty } \frac { ( - 1 ) ^ { n } t ^ { 4 n + 3 } } { ( 4 n + 3 ) }$

Question

Quizplus · Accepted Answer

The Answer is B

Evaluate the Indefinite Integral as a Power Series ∫tan⁡−1(t2)dt\int \tan ^ { - 1 } \left( t ^ { 2 } \right) d t∫tan−1(t2)dt

Evaluate the Indefinite Integral as a Power Series $\int \tan ^ { - 1 } \left( t ^ { 2 } \right) d t$