The region under the graph of $y=\frac{7}{x(x+1)}$ on the interval [1, 2] is revolved about the x-axis. Find the volume of the resulting solid.

Name: The region under the graph of $y=\frac{7}{x(x+1)}$ on the interval [1, 2] is revolved about the x-axis. Find the volume of the resulting solid.
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The Answer of The region under the graph of $y=\frac{7}{x(x+1)}$ on the interval [1, 2] is revolved about the x-axis. Find the volume of the resulting solid.

The Region Under the Graph Of y=7x(x+1)y=\frac{7}{x(x+1)}y=x(x+1)7​ On the Interval [1, 2] Is Revolved About the X-Axis

The Region Under the Graph Of $y=\frac{7}{x(x+1)}$ On the Interval [1, 2] Is Revolved About the X-Axis