Find the integral using an appropriate trigonometric substitution. $\int x \sqrt{9-x^{2}} d x$
A) $\frac{1}{3}\left(9-x^{2}\right)^{3 / 2}+C$
B) $-\frac{1}{3} x^{2}\left(9-x^{2}\right)^{3 / 2}+C$
C) $\frac{1}{3} x^{2}\left(9-x^{2}\right)^{3 / 2}+C$
D) $-\frac{1}{3}\left(9-x^{2}\right)^{3 / 2}+C$

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The Answer of Find the integral using an appropriate trigonometric substitution. $\int x \sqrt{9-x^{2}} d x$
A) $\frac{1}{3}\left(9-x^{2}\right)^{3 / 2}+C$
B) $-\frac{1}{3} x^{2}\left(9-x^{2}\right)^{3 / 2}+C$
C) $\frac{1}{3} x^{2}\left(9-x^{2}\right)^{3 / 2}+C$
D) $-\frac{1}{3}\left(9-x^{2}\right)^{3 / 2}+C$

Find the Integral Using an Appropriate Trigonometric Substitution ∫x9−x2dx\int x \sqrt{9-x^{2}} d x∫x9−x2​dx

Find the Integral Using an Appropriate Trigonometric Substitution $\int x \sqrt{9-x^{2}} d x$