The quantity demanded per month of an item is related to the unit price by the demand equation $p=\frac{40}{0.05 x^{2}+5}$ , $0 \leq x \leq 20$ where p is measured in dollars and x is measured in units of a thousand. How many items must be sold by the manufacturer to maximize its revenue?
Hint: Recall that the revenue is given by $R=p x$

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The Answer of The quantity demanded per month of an item is related to the unit price by the demand equation $p=\frac{40}{0.05 x^{2}+5}$ , $0 \leq x \leq 20$ where p is measured in dollars and x is measured in units of a thousand. How many items must be sold by the manufacturer to maximize its revenue?
Hint: Recall that the revenue is given by $R=p x$

The Quantity Demanded Per Month of an Item Is Related p=400.05x2+5p=\frac{40}{0.05 x^{2}+5}p=0.05x2+540​

The Quantity Demanded Per Month of an Item Is Related $p=\frac{40}{0.05 x^{2}+5}$