Use implicit differentiation to find an equation of the tangent line to the curve at the given point. $y \sin 3 x=x \cos 3 y,\left(\frac{\pi}{3}, \frac{\pi}{6}\right)$
A) $y=\frac{x}{3}$
B) $y=\frac{x}{3}+\frac{\pi}{6}$
C) $y=2 x-\frac{3 \pi}{3}$
D) $y=\frac{x}{6}$
E) $y=-\frac{x}{2}+\frac{\pi}{2}$

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The Answer of Use implicit differentiation to find an equation of the tangent line to the curve at the given point. $y \sin 3 x=x \cos 3 y,\left(\frac{\pi}{3}, \frac{\pi}{6}\right)$
A) $y=\frac{x}{3}$
B) $y=\frac{x}{3}+\frac{\pi}{6}$
C) $y=2 x-\frac{3 \pi}{3}$
D) $y=\frac{x}{6}$
E) $y=-\frac{x}{2}+\frac{\pi}{2}$

Use Implicit Differentiation to Find an Equation of the Tangent ysin⁡3x=xcos⁡3y,(π3,π6)y \sin 3 x=x \cos 3 y,\left(\frac{\pi}{3}, \frac{\pi}{6}\right)ysin3x=xcos3y,(3π​,6π​)

Use Implicit Differentiation to Find an Equation of the Tangent $y \sin 3 x=x \cos 3 y,\left(\frac{\pi}{3}, \frac{\pi}{6}\right)$