Find an equation of the tangent line to the given curve at the indicated point. $\frac{1}{13} y^{2}-x^{3}-x^{2}=0 ; \quad(1, \sqrt{26})$

Name: Find an equation of the tangent line to the given curve at the indicated point. $\frac{1}{13} y^{2}-x^{3}-x^{2}=0 ; \quad(1, \sqrt{26})$
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The Answer of Find an equation of the tangent line to the given curve at the indicated point. $\frac{1}{13} y^{2}-x^{3}-x^{2}=0 ; \quad(1, \sqrt{26})$

Find an Equation of the Tangent Line to the Given 113y2−x3−x2=0;(1,26)\frac{1}{13} y^{2}-x^{3}-x^{2}=0 ; \quad(1, \sqrt{26})131​y2−x3−x2=0;(1,26​)

Find an Equation of the Tangent Line to the Given $\frac{1}{13} y^{2}-x^{3}-x^{2}=0 ; \quad(1, \sqrt{26})$