A 6.0-kg block slides from rest at position A down a frictionless incline to position B. The speed of the block at B is

Question

Quizplus · Accepted Answer

Using conservation of energy, we can find the speed of the block at point B. The potential energy at point A is equal to the kinetic energy at point B, so:

mgh = (1/2)mv^2

where m is the mass of the block, g is the acceleration due to gravity, h is the height difference between A and B, and v is the velocity of the block at point B.

Plugging in the given values, we get:

(6 kg)(9.8 m/s^2)(5.2 m) = (1/2)(6 kg)v^2

Solving for v, we get:

v = √(2gh) = √(2(9.8 m/s^2)(5.2 m)) = 4.4 m/s

Therefore, the best choice is B.

A 60-Kg Block Slides from Rest at Position a Down a a Frictionless