Question 1

A uniform electric field,with a magnitude of 600 N/C,is directed parallel to the positive x-axis.If the potential at x = 3.0 m is 1 000 V,what is the change in potential energy of a proton as it moves from x = 3.0 m to x = 1.0 m? (q_p = 1.6 x 10^-19 C)

Accepted Answer

The change in potential energy of a charged particle moving through an electric field is given by ΔPE = qΔV, where q is the charge of the particle and ΔV is the change in potential.

Here, the potential difference between x = 3.0 m and x = 1.0 m is ΔV = V(1.0 m) - V(3.0 m) = (600 N/C) * (2.0 m) = 1200 V.

For a proton, q = 1.6 x 10^-19 C. Thus, ΔPE = (1.6 x 10^-19 C) * (1200 V) = 1.9 x 10^-16 J.

Therefore, the correct answer is B, 1.9 x 10^-16 J.

Question 2

A proton (+1.6 x 10^-19C)moves 10 cm along the direction of an electric field of strength 3.0 N/C.The electrical potential difference between the proton's initial and ending points is:

Accepted Answer

Electric potential difference (V) = Electric field strength (E) × Distance (d)

V = E × d

Here, 
E = 3.0 N/C (given) 
d = 10 cm = 0.1 m (given)

Therefore,

V = 3.0 N/C × 0.1 m 
V = 0.30 V

So, the answer is option B.

Question 3

An electron is released from rest at the negative plate of a parallel-plate capacitor.If the distance across the plate is 5.0 mm and the potential difference across the plate is 5.0 V,with what velocity does the electron hit the positive plate? (m_e = 9.1 x 10^-31 kg,e = 1.6 x 10^-19 C)

Accepted Answer

The kinetic energy gained by the electron is equal to the work done by the electric field, which is the charge times the potential difference (eV). Using the equation $ \frac{1}{2}mv^2 = eV $, solve for $ v $: $ v = \sqrt{\frac{2eV}{m}} $. Substituting the given values, $ v = \sqrt{\frac{2 \times 1.6 \times 10^{-19} \times 5}{9.1 \times 10^{-31}}} \approx 1.3 \times 10^6 $ m/s.

Question 4

If an electron is accelerated from rest through a potential difference of 1 200 V,find its approximate velocity at the end of this process.(e = 1.6 x 10^-19 C;m_e = 9.1 x 10^-31 kg)

Accepted Answer

The answer of If an electron is accelerated from rest...

Question 5

The unit of electrical potential,the volt,is dimensionally equivalent to:

Accepted Answer

The unit of electrical potential, the volt, is defined as the amount of work required to move one coulomb of charge through a circuit. Therefore, its dimensional equivalence is J/C, or joules per coulomb. Choices A, C, and D do not correctly represent the dimensional equivalence of volts.

Question 6

A free electron is in an electric field.With respect to the field,it experiences a force acting:

Accepted Answer

A free electron experiences a force in the direction opposite to the electric field because it has a negative charge, and the direction of the force on a charge in an electric field is given by the charge times the electric field vector.

Question 7

A proton (+1.6 x 10^-19 C)moves 10 cm on a path in the direction of a uniform electric field of strength 3.0 N/C.How much work is done on the proton by the electrical field?

Accepted Answer

The work done by an electric field on a charge is given by W = qEd, where q is the charge, E is the electric field strength, and d is the distance moved in the direction of the field. Substituting the given values: W = (1.6 x 10^-19 C)(3.0 N/C)(0.1 m) = 4.8 x 10^-20 J.

Question 8

Which of the following characteristics are held in common by both gravitational and electrostatic forces when dealing with either point masses or charges?

Accepted Answer

All three characteristics, inverse square distance law, conservative forces, and potential energy dependence on distance, hold true for both gravitational and electrostatic forces when dealing with either point masses or charges.

Question 9

A uniform electric field,with a magnitude of 600 N/C,is directed parallel to the positive x-axis.If the potential at x = 3.0 m is 1 000 V,what is the potential at x = 1.0 m?

Accepted Answer

The answer of A uniform electric field,with a magnitude of...

Question 10

If the distance between two isolated parallel plates that are oppositely charged is doubled,the electric field between the plates is essentially unchanged.However,the:

Accepted Answer

The electric field between the plates is given by E = V/d, where V is the potential difference between the plates and d is the distance between them. Since the distance is doubled but the electric field remains unchanged, the potential difference must double to maintain the same electric field strength. The charge on each plate and the force on a charged particle halfway between the plates are not affected by the change in distance.

Question 11

If the distance between two negative point charges is increased by a factor of three,the resultant potential energy is what factor times the initial potential energy?

Accepted Answer

The answer of If the distance between two negative point...

Question 12

An electron in a cathode ray tube is accelerated through a potential difference of 5.0 kV.What kinetic energy does the electron gain in the process? (e = 1.6 x 10^-19C)

Accepted Answer

The kinetic energy gained by an electron accelerating through a potential difference (V) is given by the formula KE = eV, where e is the charge of an electron. Substituting the given values, we get KE = (1.6 x 10^-19 C) x (5.0 x 10^3 V) = 8.0 x 10^-16 J. Therefore, the correct answer is option B.

Question 13

In which case does an electric field do positive work on a charged particle?

Accepted Answer

The answer of In which case does an electric field...

Question 14

An ion is released from rest and moves due to the force from an electric field from a position in the field having a potential of 14 V to a position having a potential of 8 V.The ion:

Accepted Answer

The ion is moving from a higher potential (14 V) to a lower potential (8 V). This means that the electric field is doing negative work on the ion, which implies that the ion must be positively charged. If the ion were negatively charged, the electric field would be doing positive work on it, resulting in an increase in potential energy. But we see that the ion is losing potential energy as it moves. Therefore, the ion must have a positive charge.

Question 15

Four point charges are on the rim of a circle of radius 10 cm.The charges are (in mC)+0.50,+1.5,-1.0,-0.50.If the electrical potential at the circle's center due to the +0.5 charge alone is 4.5 x 10⁴ V,what is the total potential at the center due to the four charges combined?

Accepted Answer

The answer of Four point charges are on the rim...

Question 16

A 9.0-V battery moves 20 mC of charge through a circuit running from its positive terminal to its negative terminal.How much energy was delivered to the circuit?

Accepted Answer

The energy delivered to the circuit is calculated using the formula: Energy (J) = Voltage (V) x Charge (C). Here, Energy = 9.0 V x 20 mC = 9.0 V x 0.020 C = 0.18 J.

Question 17

An electron (charge -1.6 x 10^-19C)moves on a path perpendicular to the direction of a uniform electric field of strength 3.0 N/C.How much work is done on the electron as it moves 15 cm?

Accepted Answer

When an electron moves perpendicular to an electric field, no work is done on it because the force and displacement are perpendicular.

Question 18

The quantity of electrical potential,the volt,is dimensionally equivalent to:

Accepted Answer

The volt is defined as the potential difference across a conductor when a current of one ampere dissipates one watt of power. It can also be expressed as the product of electric field (E) and distance (d), hence dimensionally equivalent to electric field times distance.

Question 19

An electron with velocity v = 1.0 x 10⁶ m/s is sent between the plates of a capacitor where the electric field is E = 500 V/m.If the distance the electron travels through the field is 1.0 cm,how far is it deviated (Y)in its path when it emerges from the electric field? (m_e = 9.1 x 10^-31 kg,e = 1.6 x 10^-19 C)

Accepted Answer

We first need to find the acceleration of the electron due to the electric field:

a = eE/m = (1.6 x 10^-19 C)(500 V/m)/(9.1 x 10^-31 kg) = 8.79 x 10^14 m/s^2

We know the distance the electron travels through the field, so we can use the kinematic equation:

Y = (1/2)at^2 = (1/2)(8.79 x 10^14 m/s^2)(1 x 10^-2 m)^2 = 4.4 x 10^-4 m = 4.4 mm

Therefore, the electron is deviated by 4.4 mm in its path when it emerges from the electric field. The answer is (B).

Question 20

A 9.0-V battery is connected between two parallel metal plates 4.0 mm apart.What is the magnitude of the electric field between the plates?

Accepted Answer

The electric field between two parallel conducting plates can be calculated using the formula:

E = V/d

where E is the electric field, V is the potential difference between the plates, and d is the distance between the plates.

In this case, the potential difference is given as 9.0 V and the distance between the plates is 4.0 mm = 0.004 m. Therefore,

E = 9.0 V / 0.004 m = 2.25 x 10^6 N/C

However, this is only the magnitude of the electric field. Since the plates are parallel and the electric field is uniform between them, the direction of the electric field is from the positive plate to the negative plate. Therefore, we need to include the negative sign to indicate the direction of the field. The answer is thus:

E = -2.3 x 10^6 N/C

Note that this is not one of the answer choices given, but the closest choice is A) 2.3 x 10^6 N/C.

Quiz 16: Electrical Energy and Capacitance

A uniform electric field,with a magnitude of 600 N/C,is directed parallel to the positive x-axis.If the potential at x = 3.0 m is 1 000 V,what is the change in potential energy of a proton as it moves from x = 3.0 m to x = 1.0 m? (q_p = 1.6 x 10^-19 C)

A proton (+1.6 x 10^-19C) moves 10 cm along the direction of an electric field of strength 3.0 N/C.The electrical potential difference between the proton's initial and ending points is:

An electron is released from rest at the negative plate of a parallel-plate capacitor.If the distance across the plate is 5.0 mm and the potential difference across the plate is 5.0 V,with what velocity does the electron hit the positive plate? (m_e = 9.1 x 10^-31 kg,e = 1.6 x 10^-19 C)

If an electron is accelerated from rest through a potential difference of 1 200 V,find its approximate velocity at the end of this process.(e = 1.6 x 10^-19 C;m_e = 9.1 x 10^-31 kg)

The unit of electrical potential,the volt,is dimensionally equivalent to:

A free electron is in an electric field.With respect to the field,it experiences a force acting:

A proton (+1.6 x 10^-19 C) moves 10 cm on a path in the direction of a uniform electric field of strength 3.0 N/C.How much work is done on the proton by the electrical field?

Which of the following characteristics are held in common by both gravitational and electrostatic forces when dealing with either point masses or charges?

A uniform electric field,with a magnitude of 600 N/C,is directed parallel to the positive x-axis.If the potential at x = 3.0 m is 1 000 V,what is the potential at x = 1.0 m?

If the distance between two isolated parallel plates that are oppositely charged is doubled,the electric field between the plates is essentially unchanged.However,the:

If the distance between two negative point charges is increased by a factor of three,the resultant potential energy is what factor times the initial potential energy?

An electron in a cathode ray tube is accelerated through a potential difference of 5.0 kV.What kinetic energy does the electron gain in the process? (e = 1.6 x 10^-19C)

In which case does an electric field do positive work on a charged particle?

An ion is released from rest and moves due to the force from an electric field from a position in the field having a potential of 14 V to a position having a potential of 8 V.The ion:

Four point charges are on the rim of a circle of radius 10 cm.The charges are (in mC) +0.50,+1.5,-1.0,-0.50.If the electrical potential at the circle's center due to the +0.5 charge alone is 4.5 x 10⁴ V,what is the total potential at the center due to the four charges combined?

A 9.0-V battery moves 20 mC of charge through a circuit running from its positive terminal to its negative terminal.How much energy was delivered to the circuit?

An electron (charge -1.6 x 10^-19C) moves on a path perpendicular to the direction of a uniform electric field of strength 3.0 N/C.How much work is done on the electron as it moves 15 cm?

The quantity of electrical potential,the volt,is dimensionally equivalent to:

A 9.0-V battery is connected between two parallel metal plates 4.0 mm apart.What is the magnitude of the electric field between the plates?

Quiz 16: Electrical Energy and Capacitance

A uniform electric field,with a magnitude of 600 N/C,is directed parallel to the positive x-axis.If the potential at x = 3.0 m is 1 000 V,what is the change in potential energy of a proton as it moves from x = 3.0 m to x = 1.0 m? (qp = 1.6 x 10-19 C)

A proton (+1.6 x 10-19 C) moves 10 cm along the direction of an electric field of strength 3.0 N/C.The electrical potential difference between the proton's initial and ending points is:

An electron is released from rest at the negative plate of a parallel-plate capacitor.If the distance across the plate is 5.0 mm and the potential difference across the plate is 5.0 V,with what velocity does the electron hit the positive plate? (me = 9.1 x 10-31 kg,e = 1.6 x 10-19 C)

If an electron is accelerated from rest through a potential difference of 1 200 V,find its approximate velocity at the end of this process.(e = 1.6 x 10-19 C;me = 9.1 x 10-31 kg)

The unit of electrical potential,the volt,is dimensionally equivalent to:

A free electron is in an electric field.With respect to the field,it experiences a force acting:

A proton (+1.6 x 10-19 C) moves 10 cm on a path in the direction of a uniform electric field of strength 3.0 N/C.How much work is done on the proton by the electrical field?

Which of the following characteristics are held in common by both gravitational and electrostatic forces when dealing with either point masses or charges?

A uniform electric field,with a magnitude of 600 N/C,is directed parallel to the positive x-axis.If the potential at x = 3.0 m is 1 000 V,what is the potential at x = 1.0 m?

If the distance between two isolated parallel plates that are oppositely charged is doubled,the electric field between the plates is essentially unchanged.However,the:

If the distance between two negative point charges is increased by a factor of three,the resultant potential energy is what factor times the initial potential energy?

An electron in a cathode ray tube is accelerated through a potential difference of 5.0 kV.What kinetic energy does the electron gain in the process? (e = 1.6 x 10-19 C)

In which case does an electric field do positive work on a charged particle?

An ion is released from rest and moves due to the force from an electric field from a position in the field having a potential of 14 V to a position having a potential of 8 V.The ion:

Four point charges are on the rim of a circle of radius 10 cm.The charges are (in mC) +0.50,+1.5,-1.0,-0.50.If the electrical potential at the circle's center due to the +0.5 charge alone is 4.5 x 104 V,what is the total potential at the center due to the four charges combined?

A 9.0-V battery moves 20 mC of charge through a circuit running from its positive terminal to its negative terminal.How much energy was delivered to the circuit?

An electron (charge -1.6 x 10-19 C) moves on a path perpendicular to the direction of a uniform electric field of strength 3.0 N/C.How much work is done on the electron as it moves 15 cm?

The quantity of electrical potential,the volt,is dimensionally equivalent to:

A 9.0-V battery is connected between two parallel metal plates 4.0 mm apart.What is the magnitude of the electric field between the plates?

A uniform electric field,with a magnitude of 600 N/C,is directed parallel to the positive x-axis.If the potential at x = 3.0 m is 1 000 V,what is the change in potential energy of a proton as it moves from x = 3.0 m to x = 1.0 m? (q_p = 1.6 x 10^-19 C)

A proton (+1.6 x 10^-19C) moves 10 cm along the direction of an electric field of strength 3.0 N/C.The electrical potential difference between the proton's initial and ending points is:

An electron is released from rest at the negative plate of a parallel-plate capacitor.If the distance across the plate is 5.0 mm and the potential difference across the plate is 5.0 V,with what velocity does the electron hit the positive plate? (m_e = 9.1 x 10^-31 kg,e = 1.6 x 10^-19 C)

If an electron is accelerated from rest through a potential difference of 1 200 V,find its approximate velocity at the end of this process.(e = 1.6 x 10^-19 C;m_e = 9.1 x 10^-31 kg)

A proton (+1.6 x 10^-19 C) moves 10 cm on a path in the direction of a uniform electric field of strength 3.0 N/C.How much work is done on the proton by the electrical field?

An electron in a cathode ray tube is accelerated through a potential difference of 5.0 kV.What kinetic energy does the electron gain in the process? (e = 1.6 x 10^-19C)

Four point charges are on the rim of a circle of radius 10 cm.The charges are (in mC) +0.50,+1.5,-1.0,-0.50.If the electrical potential at the circle's center due to the +0.5 charge alone is 4.5 x 10⁴ V,what is the total potential at the center due to the four charges combined?

An electron (charge -1.6 x 10^-19C) moves on a path perpendicular to the direction of a uniform electric field of strength 3.0 N/C.How much work is done on the electron as it moves 15 cm?