The average electrical current delivered if 1.00 g of zinc were oxidized to zinc(II)in 60.0 s is ________

Question

Quizplus · Accepted Answer

To find the average current, use the formula I = Q/t, where Q is the charge and t is the time. First, calculate moles of zinc: 1.00 g Zn / 65.38 g/mol = 0.0153 mol. Since Zn is oxidized to Zn(II), it loses 2 electrons per atom, so the total moles of electrons is 0.0153 mol * 2 = 0.0306 mol. Convert moles of electrons to charge: 0.0306 mol * 96485 C/mol = 2953.5 C. Finally, divide by time: 2953.5 C / 60.0 s = 49.2 A.

The Average Electrical Current Delivered If 1 ×\times× 10-2 A ×\times× 10-2 A

The Average Electrical Current Delivered If 1 $\times$ 10^-2 A $\times$ 10^-2 A