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Tukey's Method for Paired Comparisons Makes the Probability of Declaring

Question 91

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Tukey's method for paired comparisons makes the probability of declaring that a difference exists between at least one pair in a set of k treatments, when no difference exists, equal to 1 - Tukey's method for paired comparisons makes the probability of declaring that a difference exists between at least one pair in a set of k treatments, when no difference exists, equal to 1 -   . .

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