A metal having a work function of 2.4 eV is illuminated with monochromatic light whose photon energy is 4.0 eV. What is the maximum kinetic energy of the photoelectrons produced by this light? (h = 6.626 × 10^-34 J ∙ s, 1 eV = 1.60 × 10^-19 J) A) 2.6 × 10^-19 J B) 3.8 × 10^-19 J C) 4.7 × 10^-19 J D) 5.5 × 10^-19 J E) 6.4 × 10^-19 J

Question

Quizplus · Accepted Answer

The maximum kinetic energy of the photoelectrons is given by the equation: KE_max = photon energy - work function. Converting the energies from eV to J: 4.0 eV = 4.0 × 1.60 × 10^-19 J = 6.4 × 10^-19 J and 2.4 eV = 2.4 × 1.60 × 10^-19 J = 3.84 × 10^-19 J. Thus, KE_max = 6.4 × 10^-19 J - 3.84 × 10^-19 J = 2.56 × 10^-19 J, which rounds to 2.6 × 10^-19 J.

A Metal Having a Work Function of 2