A stopping potential of 0.50 V is required when a phototube is illuminated with monochromatic light of wavelength 590 nm. Monochromatic light of a different wavelength is now shown on the tube, and the stopping potential is measured to be 2.30 V. What is the wavelength of this new light? (c = 3.00 × 10⁸ m/s, e = - 1.60 × 10^-19 C, h = 6.626 × 10^-34 J ∙ s, 1 eV = 1.60 × 10^-19 J) A) 320 nm B) 300 nm C) 340 nm D) 360 nm E) 410 nm

Question

Quizplus · Accepted Answer

The correct answer is A because the energy of a photon is proportional to its frequency, which is inversely proportional to its wavelength. Therefore, a shorter wavelength (higher frequency) photon will have a higher energy and will require a higher stopping potential.

A Stopping Potential of 0