If the intensity of an electromagnetic wave is 80 MW/m²,what is the amplitude of the magnetic field of this wave? (c = 3.0 × 10⁸ m/s,μ₀ = 4π × 10^-7 T ∙ m/A, ε₀ = 8.85 × 10^-12 C²/N ∙ m²) A)0.82 mT B)0.33 µT C)10 T D)14 T E)0.58 mT

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The intensity of an electromagnetic wave is given by:$$I = \frac{1}{2} c \varepsilon_0 E_0^2 = \frac{1}{2} c \mu_0 H_0^2$$where:* I is the intensity in W/m^2* c is the speed of light in m/s* ε0 is the permittivity of free space in F/m* E0 is the amplitude of the electric field in V/m* μ0 is the permeability of free space in H/m* H0 is the amplitude of the magnetic field in A/mWe are given that I = 80 MW/m^2 and c = 3.0 × 10^8 m/s. We can use the above equation to solve for H0:$$H_0 = \sqrt{\frac{2I}{\mu_0 c}}$$$$H_0 = \sqrt{\frac{2(80 	imes 10^6 	ext{ W/m}^2)}{4\pi 	imes 10^{-7} 	ext{ T} \cdot 	ext{m/A} 	imes 3.0 	imes 10^8 	ext{ m/s}}}$$$$H_0 = 0.82 	ext{ mT}$$Therefore, the amplitude of the magnetic field of this wave is 0.82 mT.

If the Intensity of an Electromagnetic Wave Is 80 MW/m2,what

If the Intensity of an Electromagnetic Wave Is 80 MW/m²,what