An electromagnetic wave has a peak electric field of 3.0 kV/m.What is the intensity of the wave? (c = 3.0 × 10⁸ m/s,μ₀ = 4π × 10^-7 T ∙ m/A,ε₀ = 8.85 × 10^-12 C²/N ∙ m²) A)24 kW/m² B)12 kW/m² C)8.0 kW/m² D)4.0 kW/m²

Question

Quizplus · Accepted Answer

The intensity (I) of an electromagnetic wave is given by the formula I = 1/2ε0cE0^2, where ε0 is the permittivity of free space, c is the speed of light, and E0 is the peak electric field. Plugging in the given values, we get I = 1/2(8.85 × 10^-12 C/N ∙ m^2)(3.0 × 10^8 m/s)(3.0 × 10^3 V/m)^2 = 12 kW/m^2. Therefore, the correct answer is choice B.

An Electromagnetic Wave Has a Peak Electric Field of 3