Assuming the radius of diatomic molecules is approximately for what pressure will the mean free path in room-temperature (20°C)nitrogen be 4.6 m? The Boltzmann constant is 1.38 × 10^-23 J/K,Avogadro's number is 6.02 × 10²³ molecules/mole,and the ideal gas constant is = 0.0821 L ∙ atm/mol ∙ K. A)4.9 × 10^-8_atm B)6.9 × 10^-8_atm C)1.5 × 10^-7_atm D)2.2 × 10^-7_atm

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The Answer of Assuming the radius of diatomic molecules is approximately for what pressure will the mean free path in room-temperature (20°C)nitrogen be 4.6 m? The Boltzmann constant is 1.38 × 10^-23 J/K,Avogadro's number is 6.02 × 10²³ molecules/mole,and the ideal gas constant is = 0.0821 L ∙ atm/mol ∙ K. A)4.9 × 10^-8_atm B)6.9 × 10^-8_atm C)1.5 × 10^-7_atm D)2.2 × 10^-7_atm

Assuming the Radius of Diatomic Molecules Is Approximately for What