The mean free path of an oxygen molecule is 2.0 × 10^-5 m,when the gas is at a pressure of 120 Pa and a temperature of 275 K.The atomic mass of oxygen is 16.0 g/mol,the Boltzmann constant is 1.38 × 10^-23 J/K,Avogadro's number is 6.02 × 10²³ molecules/mole,and the ideal gas constant is J/mol ∙ K = 0.0821 L ∙ atm/mol ∙ K.The radius of an oxygen molecule is closest to A)0.22 nm. B)0.24 nm. C)0.26 nm. D)0.28 nm. E)0.30 nm.

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The Answer of The mean free path of an oxygen molecule is 2.0 × 10^-5 m,when the gas is at a pressure of 120 Pa and a temperature of 275 K.The atomic mass of oxygen is 16.0 g/mol,the Boltzmann constant is 1.38 × 10^-23 J/K,Avogadro's number is 6.02 × 10²³ molecules/mole,and the ideal gas constant is J/mol ∙ K = 0.0821 L ∙ atm/mol ∙ K.The radius of an oxygen molecule is closest to A)0.22 nm. B)0.24 nm. C)0.26 nm. D)0.28 nm. E)0.30 nm.

The Mean Free Path of an Oxygen Molecule Is 2