Given the following simplified classes,
Class Pet
{
Public:
Virtual void print);
String name;
Private:
};
Class Dog: public Pet
{
Public:
Void print);
String breed;
};
Dog vDog;
Pet vPet;
VDog.name="rover";
VDog.breed = "Collie";
Which of the following statements are not legal?
A) vPet=vDog; cout

Question

Given the following simplified classes,
Class Pet
{
Public:
Virtual void print);
String name;
Private:
};
Class Dog: public Pet
{
Public:
Void print);
String breed;
};
Dog vDog;
Pet vPet;
VDog.name="rover";
VDog.breed = "Collie";
Which of the following statements are not legal?
A) vPet=vDog; cout << vDog.name;
B) vPet=vDog; cout << vDog.breed;
C) vPet=vDog; cout << vPet.name;
D) vPet=vDog; cout << vPet.breed;

Quizplus · Accepted Answer

Option D is not legal because the base class Pet does not have a member variable called breed. Therefore, it would not be possible to access the breed member variable of the derived class Dog through the base class Pet object. Options A, B, and C are legal because the Pet class has a member variable called name, which is inherited by the derived class Dog, and can be accessed through a base-class reference to a derived-class object. Option A will print "rover" because it is accessing the name member variable of the Dog object through a base-class reference. Option B will not compile because Dog's breed member is being accessed through vDog, which is a base-class reference. Option C will print "rover" because vPet is assigned the value of VDog and print makes a virtual call to Dog's print method.

Given the Following Simplified Classes