One parent has one copy of a dominant allele for gene 87 and one recessive allele for Gene 87.The other parent has two copies of the recessive allele for Gene 87.What is the chance that their children will inherit the dominant condition (two copies of Gene 87)? You may need to draw a Punnett square to figure this out.

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The dominant condition is homozygous dominant (BB). The recessive condition is homozygous recessive (bb). The heterozygous condition is Bb.The first parent has the genotype Bb. The second parent has the genotype bb.The Punnett square for this cross is:```| | B | b ||---|---|---|| b | Bb | bb || b | Bb | bb |```As you can see from the Punnett square, there is a 25% chance that the children will inherit the dominant condition (two copies of Gene 87).

One Parent Has One Copy of a Dominant Allele for Gene