For the reaction A $\rightarrow$ B,$\Delta$G'° = -60 kJ/mol.The reaction is started with 10 mmol of A;no B is initially present.After 24 hours,analysis reveals the presence of 2 mmol of B,8 mmol of A.Which is the most likely explanation?
A)A and B have reached equilibrium concentrations.
B)An enzyme has shifted the equilibrium toward A.
C)B formation is kinetically slow;equilibrium has not been reached by 24 hours.
D)Formation of B is thermodynamically unfavorable.
E)The result described is impossible,given the fact that$\Delta$G'° is -60 kJ/mol.

Question

Quizplus · Accepted Answer

The Answer is C

For the Reaction A →\rightarrow→ B Δ\DeltaΔ G'° = -60 KJ/mol Δ\DeltaΔ G'° Is -60 KJ/mol

For the Reaction A $\rightarrow$ B $\Delta$ G'° = -60 KJ/mol $\Delta$ G'° Is -60 KJ/mol