Calculate ?G° for the reaction below at 25.0°C.
P₄O₁₀(s) + 6H₂O(l) ? 4H₃PO₄(l)
$\begin{array}{lll}\text { Species } & \Delta H_{\mathrm{f}}^{\circ}(\mathrm{kJ} / \mathrm{mol}) & S^{\circ}(\mathrm{J} / \mathrm{mol} \cdot \mathrm{K}) \\\hline \mathrm{P}_{4} \mathrm{O}_{10}(s) & -2984.0 & 228.9 \\\mathrm{H}_{2} \mathrm{O}(l) & -285.8 & 69.95 \\\mathrm{H}_{3} \mathrm{PO}_{4}(l) & -1279.0 & 110.5\end{array}$

Question

Calculate ?G° for the reaction below at 25.0°C.
P₄O₁₀(s) + 6H₂O(l) ? 4H₃PO₄(l)

\begin{array}{lll}\text { Species } & \Delta H_{\mathrm{f}}^{\circ}(\mathrm{kJ} / \mathrm{mol}) & S^{\circ}(\mathrm{J} / \mathrm{mol} \cdot \mathrm{K}) \\\hline \mathrm{P}_{4} \mathrm{O}_{10}(s) & -2984.0 & 228.9 \\\mathrm{H}_{2} \mathrm{O}(l) & -285.8 & 69.95 \\\mathrm{H}_{3} \mathrm{PO}_{4}(l) & -1279.0 & 110.5\end{array}

Quizplus · Accepted Answer

The Answer of Calculate ?G° for the reaction below at 25.0°C. P₄O₁₀(s)+ 6H₂O(l)? 4H₃PO₄(l) $\begin{array}{lll} \text { Species } & \Delta H_{\mathrm{f}}^{\circ}(\mathrm{kJ} / \mathrm{mol}) & S^{\circ}(\mathrm{J} / \mathrm{mol} \cdot \mathrm{K}) \ \hline \mathrm{P}_{4} \mathrm{O}_{10}(s) & -2984.0 & 228.9 \ \mathrm{H}_{2} \mathrm{O}(l) & -285.8 & 69.95 \ \mathrm{H}_{3} \mathrm{PO}_{4}(l) & -1279.0 & 110.5 \end{array}$

Calculate ?G° for the Reaction Below at 25 A) -61191 KJ B) -632

Calculate ?G° for the Reaction Below at 25 A) -61191 KJ
B) -632