At 25°C,the equilibrium constant for the following reaction,
Cu²⁺(aq) + Zn(s) → Cu(s) + Zn²⁺(aq) Is 1.9 × 10³⁷.
Calculate ΔG° for this reaction.(R = 8.31 × 10−³ kJ/K)

Question

At 25°C,the equilibrium constant for the following reaction, Cu²⁺(aq)+ Zn(s)→ Cu(s)+ Zn²⁺(aq) Is 1.9 × 10³⁷. Calculate ΔG° for this reaction.(R = 8.31 × 10−³ kJ/K)

Quizplus · Accepted Answer

ΔG° can be calculated using the formula ΔG° = -RTlnK. Substituting the given values (R = 8.31 × 10^-3 kJ/K, T = 298 K, K = 1.9 × 10^37), we find ΔG° = -213 kJ.

At 25°C,the Equilibrium Constant for the Following Reaction