The value of the equilibrium constant for the following reaction is
345. A + 2B ⇌ 3C + D
What is the value of the equilibrium constant for the reaction below?
2A + 4B ⇌ 6C + 2D
A) K = 345
B) K = (345) 2 = 1.19 × 105
C) K = (345) 1/2 = 18.6
D) K = (2 × 345) 2 = 4.76 × 105
E) K = 2 × (345) 2 = 2.38 × 105
Correct Answer:
Verified
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