At 25°C,the partial pressure of gases at equilibrium are as follows: N₂ = 0.12 atm,O₂ = 0.040 atm,and NO = 4.5 × 10−¹⁷ atm.What is the value of the equilibrium constant,K?
N₂(g) + O₂(g) ⇌ 2NO(g)

Question

Quizplus · Accepted Answer

The equilibrium constant expression for the reaction is K = (P_NO)^2 / (P_N2 * P_O2). Substituting the given partial pressures into this expression gives K = (4.5 × 10^-17)^2 / (0.12 * 0.040), which simplifies to approximately 4.2 × 10^-31.

At 25°C,the Partial Pressure of Gases at Equilibrium Are as Follows