If 16.4 g of oxygen gas react with excess hydrogen,what mass of water is produced? 2H₂(g)+ O₂(g)→ 2H₂O(g)

Question

Quizplus · Accepted Answer

The balanced chemical equation for the reaction between hydrogen gas and oxygen gas to produce water is $2H_2 + O_2 \rightarrow 2H_2O$. From the equation, 1 mole of $O_2$ (32.0 g) reacts with hydrogen to produce 2 moles of $H_2O$ (2 x 18.0 g = 36.0 g). Given 16.4 g of $O_2$, we use the ratio from the balanced equation to find the mass of water produced: $16.4 \, \text{g} \, O_2 \times \frac{36.0 \, \text{g} \, H_2O}{32.0 \, \text{g} \, O_2} = 18.45 \, \text{g} \, H_2O$, which rounds to 18.5 g.

If 164 G of Oxygen Gas React with Excess Hydrogen,what Mass