A weather balloon was initially at a pressure of 0.950 atm, and its volume was 35.0 L. The pressure decreased to 0.750 atm, without loss of gas or change in temperature. What was the change in the volume?

Question

Quizplus · Accepted Answer

According to Boyle's Law (P1V1 = P2V2), the volume increases when pressure decreases, if temperature and amount of gas remain constant. Calculating the new volume: V2 = (P1V1)/P2 = (0.950 atm * 35.0 L) / 0.750 atm = 44.3 L. The change in volume is 44.3 L - 35.0 L = 9.3 L.

A Weather Balloon Was Initially at a Pressure of 0