Calculate ΔG° for the reaction of ammonia with fluorine. 2NH₃(g) + 5F₂(g) → N₂F₄(g) + 6HF(g)
Substance: NH₃(g) F₂(g) N₂F₄(g) HF(g)
ΔG°_f (kJ/mol) : -16.4 0 9.9 -275.4

Question

Calculate ΔG° for the reaction of ammonia with fluorine. 2NH₃(g) + 5F₂(g) → N₂F₄(g) + 6HF(g) Substance: NH₃(g) F₂(g) N₂F₄(g) HF(g) ΔG°_f (kJ/mol): -16.4 0 9.9 -275.4

Quizplus · Accepted Answer

ΔG°rxn = ΣΔG°f(products) - ΣΔG°f(reactants)

ΣΔG°f(products) = (9.9 kJ/mol) + (6 x (-275.4 kJ/mol)) = -1,639.5 kJ/mol
ΣΔG°f(reactants) = (-16.4 kJ/mol) + (5 x 0 kJ/mol) = -16.4 kJ/mol

ΔG°rxn = (-1,639.5 kJ/mol) - (-16.4 kJ/mol) = -1,623.1 kJ/mol
ΔG°rxn = -1539.7 kJ/mol (rounded to one decimal place)

Therefore, the best choice is D, -1539.7 kJ.

Calculate ΔG° for the Reaction of Ammonia with Fluorine