For a reaction,Δ_rH° = -208.8 kJ and Δ_rS° = -308.2 J/K.At what temperature will Δ_rG° = 0.00 kJ? A) 0.68 K B) 677.5 K C) 1476 K D) 6435 K E) 0.85 K

Question

Quizplus · Accepted Answer

We know that:
ΔG° = ΔH° - TΔS°
At equilibrium, ΔG° = 0
Therefore:
0 = -208.8 kJ - T(-308.2 J/K)
0 = -208.8 kJ + 0.3082 kJ K⁻¹ T
T = (208.8 kJ)/(0.3082 kJ K⁻¹) = 677.5 K

Therefore, the best choice is B.

For a Reaction,ΔrH° = -208

For a Reaction,Δ_rH° = -208