Titration of 0.1615 g of an unknown monoprotic acid dissolved in 25.00 mL of water requires 21.84 mL of 0.1231 M NaOH to reach the endpoint.What is the molar mass of the acid?
A) 60 g/mol
B) 0.01665 g/mol
C) 52.46 g/mol
D) 0.9100 g/mol
E) 2.718 g/mol

Question

Quizplus · Accepted Answer

The Answer of Titration of 0.1615 g of an unknown monoprotic acid dissolved in 25.00 mL of water requires 21.84 mL of 0.1231 M NaOH to reach the endpoint.What is the molar mass of the acid?
A) 60 g/mol
B) 0.01665 g/mol
C) 52.46 g/mol
D) 0.9100 g/mol
E) 2.718 g/mol