How many moles of sulfate ions are there in a 0.650-L solution of 0.312 M Al₂(SO₄)₃?

Question

Quizplus · Accepted Answer

The formula Al(SO4)3 indicates that there are three sulfate ions per one aluminum ion. 
To find the number of moles of sulfate ions present in the solution, we need to calculate the total moles of Al(SO4)3 present in the solution and then multiply it by the number of sulfate ions per one Al(SO4)3 molecule.

moles Al(SO4)3 = volume of solution (L) x molarity of solution

moles Al(SO4)3 = 0.650 L x 0.312 mol/L

moles Al(SO4)3 = 0.203 mol

To find the number of moles of sulfate ions, we need to multiply the moles of Al(SO4)3 by the number of sulfate ions per one Al(SO4)3 molecule.

moles of sulfate ions = moles of Al(SO4)3 x 3

moles of sulfate ions = 0.203 mol x 3

moles of sulfate ions = 0.608 mol

Therefore, the answer is B) 0.608 mol.

How Many Moles of Sulfate Ions Are There in a 0.650-L