A dilute solution is prepared by transferring 35.00 mL of a 0.6363 M stock solution to a 900.0 mL volumetric flask and diluting to mark.What is the molarity of this dilute solution?

Question

Quizplus · Accepted Answer

The molarity of the dilute solution can be calculated using the dilution formula $M_1V_1 = M_2V_2$, where $M_1$ and $V_1$ are the molarity and volume of the initial solution, and $M_2$ and $V_2$ are the molarity and volume of the final solution. Substituting the given values, $0.6363 \, \text{M} \times 35.00 \, \text{mL} = M_2 \times 900.0 \, \text{mL}$. Solving for $M_2$ gives $M_2 = \frac{0.6363 \, \text{M} \times 35.00 \, \text{mL}}{900.0 \, \text{mL}} = 0.02474 \, \text{M}$.

A Dilute Solution Is Prepared by Transferring 35