What is the molarity of an NaI solution that contains 4.5 g of NaI in 21.0 mL of solution?

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Quizplus · Accepted Answer

To find the molarity, first convert grams of NaI to moles. The molar mass of NaI (sodium iodide) is approximately 149.89 g/mol. So, $4.5 \, \text{g NaI} \times \frac{1 \, \text{mol}}{149.89 \, \text{g}} = 0.030 \, \text{mol NaI}$. Then, convert the volume from mL to L: $21.0 \, \text{mL} = 0.021 \, \text{L}$. Finally, molarity $M = \frac{\text{moles of solute}}{\text{liters of solution}} = \frac{0.030 \, \text{mol}}{0.021 \, \text{L}} \approx 1.4 \, \text{M}$.

What Is the Molarity of an NaI Solution That Contains