Complete combustion of a 0.70-mol sample of a hydrocarbon,C_xH_y,gives 2.80 mol of CO₂ and 3.50 mol of H₂O.The molecular formula of the original hydrocarbon is

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The combustion of the hydrocarbon produces 2.80 mol of CO2, indicating 2.80 mol of carbon atoms, and 3.50 mol of H2O, indicating 7.00 mol of hydrogen atoms. The ratio of carbon to hydrogen is 4:10, which corresponds to C4H10.

Complete Combustion of a 0