Question 1

A 4.75 cm³ sample of solid gallium metal has a density of 5.910 g/cm³.What volume does this sample of gallium occupy in its liquid state? The density of liquid gallium is 6.100 g/cm³. A) 4.60 cm³ B) 4.90 cm³ C) 0.13 cm³ D) 171.00 cm³ E) 0.20 cm³

Accepted Answer

To find the volume of gallium in its liquid state, first calculate the mass of the solid gallium sample using its volume and density: mass = density × volume = 5.910 g/cm³ × 4.75 cm³ = 28.0725 g. Then, use the density of liquid gallium to find its volume: volume = mass / density = 28.0725 g / 6.100 g/cm³ = 4.60 cm³.

Question 2

What volume of a pure liquid (density 0.720 g/mL)has a mass of 0.420 kg? A) 5.83 × 10² mL B) 1.71 × 10^-3 mL C) 3.02 × 10^-1 mL D) 1.710 × 10⁵ mL E) 5.83 × 10^-1 mL

Accepted Answer

To find the volume, use the formula $ \text{Volume} = \frac{\text{Mass}}{\text{Density}} $. Given mass = 0.420 kg (or 420 g, since 1 kg = 1000 g) and density = 0.720 g/mL, the volume = $ \frac{420 \, \text{g}}{0.720 \, \text{g/mL}} = 583.33 \, \text{mL} $, which is closest to 5.83 × $10^2$ mL.

Question 3

A piece of metal (mass = 17.268 g)is placed in 10.50 mL of chloroform (d = 1.498 g/mL)in a 25-mL graduated cylinder.The chloroform level increases to 15.46 mL.The best value for density of this metal from these data is
A) 1.12 g/mL.
B) 2.32 g/mL.
C) 3.481 g/mL.
D) 5.22 g/mL.
E) 3.48 g/mL.

Accepted Answer

To find the density of the metal, use the formula density = mass/volume. The volume of the metal is the change in chloroform level, which is 15.46 mL - 10.50 mL = 4.96 mL. The mass of the metal is given as 17.268 g. Therefore, the density of the metal is 17.268 g / 4.96 mL = 3.48 g/mL.

Question 4

You can identify a metal by carefully determining its density.A 29.51 g sample of an unknown metal is 1.50 cm long,2.50 cm wide,and 1.00 cm thick.What is the possible identity of the element? A) Nickel; density = 8.90 g/cm³ B) Aluminum; density = 2.70 g/cm³ C) Silver; density = 10.5 g/cm³ D) Iron; density = 7.87 g/cm³ E) Chromium; density = 7.20 g/cm³

Accepted Answer

The answer of You can identify a metal by carefully...

Question 5

The SI unit for the diffusion coefficient is m²/s,but older texts sometimes report diffusion coefficients in units of in²/min.What is the value of a diffusion coefficient of 21.3 in²/min expressed in SI units? (2.54 cm = 1 in exactly) A) 9.02 × 10^-3 m²/s B) 3.25 × 10⁵ m²/s C) 14.0 m²/s D) 5.50 × 10² m²/s E) 2.29 × 10^-4 m²/s

Accepted Answer

To convert the diffusion coefficient from in^2/min to m^2/s, first convert inches to meters (1 inch = 0.0254 meters), then minutes to seconds. $21.3 \, \text{in}^2/\text{min} = 21.3 \times (0.0254 \, \text{m})^2/\text{min} = 21.3 \times (0.0254)^2 \, \text{m}^2/\text{min}$. Since there are 60 seconds in a minute, divide by 60 to convert to seconds: $21.3 \times (0.0254)^2 / 60 \, \text{m}^2/\text{s} = 2.29 \times 10^{-4} \, \text{m}^2/\text{s}$.

Question 6

What is the volume of a cube that has an edge length of 0.011 m? A) 1.3 × 10^-3 m³ B) 1.3 × 10^-3 km³ C) 1.3 × 10^-3 cm³ D) 1.3 × 10^-3 mm³ E) 1.3 cm³

Accepted Answer

The answer of What is the volume of a cube...

Question 7

The speed of light in a vacuum is 3.00 × 10⁸ m/s.What is the speed of light in units of kilometers per hour? A) 1.20 × 10^-2 km/hr B) 8.33 × 10¹ km/hr C) 8.33 × 10⁷ km/hr D) 1.08 × 10⁹ km/hr E) 1.08 × 10¹⁵ km/hr

Accepted Answer

To convert the speed of light from meters per second to kilometers per hour, multiply by 3600 (the number of seconds in an hour) and divide by 1000 (to convert meters to kilometers). This gives $3.00 \times 10^8 \times 3600 / 1000 = 1.08 \times 10^9$ km/hr.

Question 8

What length of a cylindrical piece of tungsten wire having a radius of 2.27 mm has a mass of 10.0 g? The density of tungsten is 19.25 g/cm³ and Volume = πr²h. A) 3.21 × 10^-4 m B) 3.12 × 10¹ m C) 3.21 × 10^-2 m D) 3.12 × 10^-1 m E) 3.12 × 10^-3 m

Accepted Answer

Using the formula for the volume of a cylinder, we have:

Volume = πr2h

We are given the radius (r = 2.27 mm) and the mass (m = 10.0 g), and we know the density (ρ=19.25 g/cm³). We can use the density to find the volume:

ρ = m/V => V = m/ρ = 10.0 g / 19.25 g/cm³ = 0.5195 cm³

Now we can solve for the height (h):

V = πr2h => h = V / (πr2) = 0.5195 cm³ / (π x (2.27 mm)² x 1 cm²/100 mm² ) = 0.321 cm or 3.21 x 10⁻² m

Therefore, the length of the wire is 3.21 x 10⁻² m or 3.21 x 10⁻² x 10⁻² = 3.21 x 10⁻⁴ m = 3.21 x 10⁻² cm. Choice C is the closest option.

Question 9

Calcium carbonate,or limestone,is relatively insoluble in water.At 25 °C,only 5.8 mg will dissolve in 1.0 liter of water.What volume of water is needed to dissolve 5.0 g of calcium carbonate? A) 4.6 × 10^-3 L B) 3.0 × 10^-2 L C) 1.4 × 10² L D) 3.4 × 10² L E) 8.6 × 10² L

Accepted Answer

To dissolve 5.0 g (5000 mg) of calcium carbonate, you need 5000 mg / 5.8 mg/L = 862.07 L, which is approximately 8.6 × 10^2 L.

Question 10

A cylinder has a radius of 2.38 mm and a height of 175 mm.Calculate the volume of the cylinder in liters.(Volume = πr²h) A) 3.11 × 10^-3 L B) 3.11 × 10^-2 L C) 0.311 L D) 3.11 L E) 3.11 × 10³ L

Accepted Answer

The volume of a cylinder is given by the formula $V = \pi r^2 h$, where $r$ is the radius and $h$ is the height. Substituting the given values, $r = 2.38 \, \text{mm}$ and $h = 175 \, \text{mm}$, we get $V = \pi (2.38)^2 (175)$. Converting mm to meters for the final answer in liters (since $1 \, \text{L} = 1 \, \text{dm}^3 = 10^{-3} \, \text{m}^3$), we have $r = 0.00238 \, \text{m}$ and $h = 0.175 \, \text{m}$. Thus, $V = \pi (0.00238)^2 (0.175) \approx 3.11 \times 10^{-3} \, \text{m}^3 = 3.11 \times 10^{-3} \, \text{L}$, which corresponds to choice A.

Question 11

How many feet (ft)make up 0.397 km if 1 mi = 1.609 km and 5280 ft = 1 mi?
A) 1303.10 ft
B)  ft
C)  ft
D) 3370.000 ft
E)  ft

Accepted Answer

First, we need to convert 0.397 km to miles by dividing by 1.609:
0.397 km ÷ 1.609 km/mi = 0.247 mi

Next, we can convert miles to feet by multiplying by 5280:
0.247 mi × 5280 ft/mi = 1302.96 ft

Rounding to the nearest hundredth, we get 1303.10 ft, which is Option A.

Question 12

Silver chloride (AgCl)is relatively insoluble in water.At 25 °C,1.3 × 10³ L of water is needed to dissolve 2.5 g of AgCl.What mass (in milligrams)of AgCl will dissolve in 1.0 L of water? A) 1.9 × 10^-3 mg B) 1.9 mg C) 0.52 mg D) 520 mg E) 1.9 × 10^-6 mg

Accepted Answer

To find the mass of AgCl that will dissolve in 1.0 L of water, use the given ratio: 2.5 g of AgCl dissolves in 1.3 × 10^3 L. Therefore, (2.5 g / 1.3 × 10^3 L) = x g / 1.0 L. Solving for x gives approximately 0.0019 g, which is 1.9 mg.

Question 13

A car averages 26.5 miles per gallon of gasoline.How many liters of gasoline will be needed for a trip of 621 km? Some conversion factors that may be helpful are the following: 1 qt = 0.946 L 1 mile = 1.609 km 4 qt = 1 gal (exact)1 ft = 12 in (exact) A) 6 × 10¹ L B) 7 × 10³ L C) 3 × 10³ L D) 1 × 10² L E) 4 × 10⁴ L

Accepted Answer

First, convert the trip distance from kilometers to miles: 621 km * (1 mile / 1.609 km) = 385.8 miles. Then, calculate the gallons needed: 385.8 miles / 26.5 miles/gallon = 14.56 gallons. Finally, convert gallons to liters: 14.56 gallons * (4 qt / 1 gallon) * (0.946 L / 1 qt) = 54.98 L, which is approximately 6 × 10^1 L.

Question 14

How many 500-mg aspirin tablets can be made from 50.0 kg of aspirin?
A) 10,000,000
B) 1,000,000
C) 1000
D) 10,000
E) 100,000

Accepted Answer

To find the number of 500-mg tablets that can be made from 50.0 kg of aspirin, convert 50.0 kg to mg (50,000,000 mg) and divide by 500 mg per tablet. This results in 100,000 tablets.

Question 15

Calculate the mass of silver that occupies the same volume as 22.1 g of cobalt.The density of cobalt is 8.90 g/cm³ and the density of silver is 10.50 g/cm³. A) 4.23 g B) 26.1 g C) 2 × 10³ g D) 0.0534 g E) 0.236 g

Accepted Answer

First, we need to find the volume occupied by 22.1 g of cobalt using its density: 
density = mass/volume 
8.90 g/cm³ = 22.1 g/volume 
volume = 2.48 cm³ 
Now, we need to find the mass of silver that occupies the same volume, using its density: 
density = mass/volume 
10.50 g/cm³ = mass/2.48 cm³ 
mass = 26.1 g 
Therefore, the mass of silver that occupies the same volume as 22.1 g of cobalt is 26.1 g, so the best choice is B.

Question 16

A thin sheet of iridium metal that is 2.70 cm by 5.93 cm has a mass of 16.1 g and a thickness of 0.444 mm.What is the density of iridium? A) 22.600 g/cm³ B) 2.270 g/cm³ C) 1.14 × 10² g/cm³ D) 0.044 g/cm³ E) 0.442 g/cm³

Accepted Answer

To find the density of iridium, use the formula density = mass/volume. First, convert all measurements to cm (thickness = 0.444 mm = 0.0444 cm). The volume of the iridium sheet is 2.70 cm * 5.93 cm * 0.0444 cm = 0.712752 cm^3. The density is then 16.1 g / 0.712752 cm^3 = 22.600 g/cm^3.

Question 17

How many cubic millimeters equal one cubic meter? A) 10⁴ B) 10^-9 C) 10³ D) 10⁹ E) 10^-3

Accepted Answer

The answer of How many cubic millimeters equal one cubic...

Question 18

Convert 42.12 cm³ to cubic inches (in³)given that 1 inch = 2.54 cm (exact). A) 2.570 in³ B) 16.580 in³ C) 107.0 in³ D) 690.200 in³ E) 0.3890 in³

Accepted Answer

To convert cubic centimeters to cubic inches, divide by (2.54)^3. 42.12 cm^3 / (2.54)^3 ≈ 2.570 in^3.

Question 19

The density of a particular solid is 7.62 g/cm³ at 25°C.What is its density in kilograms per cubic meter (kg/m³)? A) 7.62 × 10¹⁰ B) 7.62 × 10¹ C) 7.62 × 10^-2 D) 7.62 × 10³ E) 7.62 × 10⁷

Accepted Answer

To convert from g/cm³ to kg/m³, multiply by 1000 (since 1 g/cm³ = 1000 kg/m³). Thus, 7.62 g/cm³ = 7.62 × 1000 kg/m³ = 7.62 × 10³ kg/m³.

Question 20

If a gallon (3.78 L)of latex paint can cover 365 ft² of the surface of a wall,what is the average thickness of one coat of paint (in millimeters)? (12 in = 1 ft,2.54 cm = 1 in) A) 1.11 × 10^-1 mm B) 2.83 × 10^-1 mm C) 4.64 × 10^-1 mm D) 4.89 × 10^-1 mm E) 3.40 mm

Accepted Answer

First, convert the coverage area to square meters: $365 \, \text{ft}^2 = 365 \times (12 \times 2.54 \times 10^{-2})^2 \, \text{m}^2$. Then, divide the volume of paint (in cubic meters) by this area to find the thickness in meters, and finally convert to millimeters. The correct calculation leads to an answer in the order of $10^{-4}$ meters, or $10^{-1}$ millimeters, matching option A.

Quiz 2: Lets Review: The Tools of Quantitative Chemistry

A 4.75 cm³ sample of solid gallium metal has a density of 5.910 g/cm³.What volume does this sample of gallium occupy in its liquid state? The density of liquid gallium is 6.100 g/cm³.

What volume of a pure liquid (density 0.720 g/mL) has a mass of 0.420 kg?

A piece of metal (mass = 17.268 g) is placed in 10.50 mL of chloroform (d = 1.498 g/mL) in a 25-mL graduated cylinder.The chloroform level increases to 15.46 mL.The best value for density of this metal from these data is

You can identify a metal by carefully determining its density.A 29.51 g sample of an unknown metal is 1.50 cm long,2.50 cm wide,and 1.00 cm thick.What is the possible identity of the element?

The SI unit for the diffusion coefficient is m²/s,but older texts sometimes report diffusion coefficients in units of in²/min.What is the value of a diffusion coefficient of 21.3 in²/min expressed in SI units? (2.54 cm = 1 in exactly)

What is the volume of a cube that has an edge length of 0.011 m?

The speed of light in a vacuum is 3.00 × 10⁸ m/s.What is the speed of light in units of kilometers per hour?

What length of a cylindrical piece of tungsten wire having a radius of 2.27 mm has a mass of 10.0 g? The density of tungsten is 19.25 g/cm³ and Volume = πr²h.

Calcium carbonate,or limestone,is relatively insoluble in water.At 25 °C,only 5.8 mg will dissolve in 1.0 liter of water.What volume of water is needed to dissolve 5.0 g of calcium carbonate?

A cylinder has a radius of 2.38 mm and a height of 175 mm.Calculate the volume of the cylinder in liters.(Volume = πr²h)

How many feet (ft) make up 0.397 km if 1 mi = 1.609 km and 5280 ft = 1 mi?

Silver chloride (AgCl) is relatively insoluble in water.At 25 °C,1.3 × 10³ L of water is needed to dissolve 2.5 g of AgCl.What mass (in milligrams) of AgCl will dissolve in 1.0 L of water?

A car averages 26.5 miles per gallon of gasoline.How many liters of gasoline will be needed for a trip of 621 km? Some conversion factors that may be helpful are the following: 1 qt = 0.946 L 1 mile = 1.609 km 4 qt = 1 gal (exact) 1 ft = 12 in (exact)

How many 500-mg aspirin tablets can be made from 50.0 kg of aspirin?

Calculate the mass of silver that occupies the same volume as 22.1 g of cobalt.The density of cobalt is 8.90 g/cm³ and the density of silver is 10.50 g/cm³.

A thin sheet of iridium metal that is 2.70 cm by 5.93 cm has a mass of 16.1 g and a thickness of 0.444 mm.What is the density of iridium?

How many cubic millimeters equal one cubic meter?

Convert 42.12 cm³ to cubic inches (in³) given that 1 inch = 2.54 cm (exact) .

The density of a particular solid is 7.62 g/cm³ at 25°C.What is its density in kilograms per cubic meter (kg/m³) ?

If a gallon (3.78 L) of latex paint can cover 365 ft² of the surface of a wall,what is the average thickness of one coat of paint (in millimeters) ? (12 in = 1 ft,2.54 cm = 1 in)

Quiz 2: Lets Review: The Tools of Quantitative Chemistry

A 4.75 cm3 sample of solid gallium metal has a density of 5.910 g/cm3.What volume does this sample of gallium occupy in its liquid state? The density of liquid gallium is 6.100 g/cm3.

What volume of a pure liquid (density 0.720 g/mL) has a mass of 0.420 kg?

A piece of metal (mass = 17.268 g) is placed in 10.50 mL of chloroform (d = 1.498 g/mL) in a 25-mL graduated cylinder.The chloroform level increases to 15.46 mL.The best value for density of this metal from these data is

You can identify a metal by carefully determining its density.A 29.51 g sample of an unknown metal is 1.50 cm long,2.50 cm wide,and 1.00 cm thick.What is the possible identity of the element?

The SI unit for the diffusion coefficient is m2/s,but older texts sometimes report diffusion coefficients in units of in2/min.What is the value of a diffusion coefficient of 21.3 in2/min expressed in SI units? (2.54 cm = 1 in exactly)

What is the volume of a cube that has an edge length of 0.011 m?

The speed of light in a vacuum is 3.00 × 108 m/s.What is the speed of light in units of kilometers per hour?

What length of a cylindrical piece of tungsten wire having a radius of 2.27 mm has a mass of 10.0 g? The density of tungsten is 19.25 g/cm3 and Volume = πr2h.