Figure 2.8
-How many grams of the compound in Figure 2.8 would be required to make 2 L of a 1 M solution?
(carbon = 12,oxygen = 16,hydrogen = 1)

Question

Quizplus · Accepted Answer

From Figure 2.8, we can see that the compound has a molecular weight of 180 g/mol (12 × 10 + 16 × 6 + 1 × 22). 
To make a 1 M solution, we need 1 mole/L of the compound. 
Therefore, to make 2 L of a 1 M solution, we need 2 moles of the compound.
2 moles of the compound would weigh 2 × 180 g = 360 g.
Therefore, we need 360 g of the compound to make 2 L of a 1 M solution. 
The closest answer choice is D) 120 g, which is half of 360 g. Therefore we need to choose D as the best choice.

Figure 2.8 -How Many Grams of the Compound in Figure 2.8 Would