Calculate the equilibrium constant for the following reaction at 298 K: 2H₂S(g) → 2H₂(g) + S₂(g) Δ_rH° = 169.8 kJ mol^-1; Δ_rS°= 78.0 J K^-1 mol^-1

Name: Calculate the equilibrium constant for the following reaction at 298 K: 2H 2 S(g) → 2H 2 (g) + S 2 (g) Δ r H° = 169.8 kJ mol -1 ; Δ r S°= 78.0 J K -1 mol -1
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The Answer of Calculate the equilibrium constant for the following reaction at 298 K: 2H₂S(g) → 2H₂(g) + S₂(g) Δ_rH° = 169.8 kJ mol^-1; Δ_rS°= 78.0 J K^-1 mol^-1

Calculate the Equilibrium Constant for the Following Reaction at 298