For the isomerization reaction: butane ⇌ isobutane
K_p equals 25.0 at 500 °C. If the initial pressures of butane and isobutane are 20.0 atm and 0.0 atm, respectively, what are the pressures of the two gases at equilibrium?

Question

Quizplus · Accepted Answer

At equilibrium, the reaction quotient Q equals the equilibrium constant Kp. Using the expression Kp = P(isobutane) / P(butane), and solving for the pressures with the given initial conditions, the pressures at equilibrium are P(butane) = 0.77 atm and P(isobutane) = 19.2 atm.

For the Isomerization Reaction: Butane ⇌ Isobutane