The Henry's law constant for helium gas in water at 30 °C is 3.70 × mol L^-1 bar^-1. When the partial pressure of helium above a sample of water is 0.450 bar, the concentration of helium in the water is ________ mol L^-1. A) 1.22 × 10³ B) 8.22 × 10^-4 C) 1.67 × 10^-4 D) 0.45 E) 3.70 × 10^-4

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Quizplus · Accepted Answer

From Henry's law, we know that concentration of gas in water = Henry's law constant × partial pressure of gas above water Plugging in the given values, we get: concentration of helium in water = (3.70 × 10eacb30_68fd_beb9_b5a4_77fb6c900833_TB7901_11_TB7901_11 mol L^-1 bar^-1) × (0.450 bar) = 1.665 mol L^-1 Rounding off to two significant figures, we get: concentration of helium in water = 1.7 × 10eacb30_68fd_beb9_b5a4_77fb6c900833_TB7901_11_TB7901_11 mol L^-1 The answer closest to this is (C) 1.67 × 10eacb30_68fd_beb9_b5a4_77fb6c900833_TB7901_11_TB7901_11 mol L^-1.

The Henry's Law Constant for Helium Gas in Water at 30