Determine the electron geometry (eg) and molecular geometry (mg) of the bolded and underlined atom CH₃OCH₃. A) eg = tetrahedral, mg = tetrahedral B) eg = linear, mg = linear C) eg = tetrahedral, mg = bent D) eg = trigonal bipyramidal, mg = tetrahedral E) eg = octahedral, mg = square planar

Question

Quizplus · Accepted Answer

The bolded and underlined atom is the central carbon atom in CH3OCH3. This carbon atom has four electron groups around it, which gives it a tetrahedral electron geometry. The molecular geometry is also tetrahedral because there are no lone pairs of electrons on the central carbon atom.

Determine the Electron Geometry (Eg) and Molecular Geometry (Mg) of the Bolded