The specific heat capacity of liquid water is 4.184 J . How many joules of heat are needed to raise the temperature of 7.00 g of water from 33.0 °C to 76.0 °C?

Question

The specific heat capacity of liquid water is 4.184 J   . How many joules of heat are needed to raise the temperature of 7.00 g of water from 33.0 °C to 76.0 °C?

Quizplus · Accepted Answer

The formula to calculate the heat needed is:

q = m * c * ΔT

where q is the heat needed, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

Substituting the given values:

q = 7.00 g * 4.184 J/g·°C * (76.0 °C - 33.0 °C)

q = 1.26 × 10^3 J

Therefore, the answer is E.

The Specific Heat Capacity of Liquid Water Is 4