How much heat is absorbed/released when 40.00 g of NH₃(g) reacts in the presence of excess (g) to produce NO(g) and H₂O(l) according to the following chemical equation?
4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(l) H° = 1168 kJ

Question

How much heat is absorbed/released when 40.00 g of NH₃(g) reacts in the presence of excess

How much heat is absorbed/released when 40.00 g of NH<sub>3</sub>(g) reacts in the presence of excess (g) to produce NO(g) and H<sub>2</sub>O(l) according to the following chemical equation? 4NH<sub>3</sub>(g) + 5O<sub>2</sub>(g) → 4NO(g) + 6H<sub>2</sub>O(l) H° = 1168 kJ A) 685.8 kJ of heat are absorbed. B) 685.8 kJ of heat are released. C) 2743 kJ of heat are absorbed. D) 2743 kJ of heat are released.

(g) to produce NO(g) and H₂O(l) according to the following chemical equation?
4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(l)

H° = 1168 kJ

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The Answer of How much heat is absorbed/released when 40.00 g of NH₃(g) reacts in the presence of excess (g) to produce NO(g) and H₂O(l) according to the following chemical equation? 4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(l) H° = 1168 kJ

How Much Heat Is Absorbed/released When 40