A balloon filled with helium gas at 20 °C occupies 4.91 L at 1.00 atm.The balloon is immersed in liquid nitrogen at -196 °C,while the pressure is raised to 5.20 atm.What is the volume of the balloon in the liquid nitrogen?
A)0.25 L
B)3.6 L
C)6.7 L
D)97 L

Question

Quizplus · Accepted Answer

To find the volume of the balloon in liquid nitrogen, we can use the combined gas law, which is $P_1V_1/T_1 = P_2V_2/T_2$, where $P$ is pressure, $V$ is volume, and $T$ is temperature in Kelvin. First, convert all temperatures to Kelvin: $T_1 = 20°C + 273.15 = 293.15 K$ and $T_2 = -196°C + 273.15 = 77.15 K$. Then, solve for $V_2$: $V_2 = \frac{P_1V_1T_2}{P_2T_1} = \frac{1.00 \, \text{atm} \times 4.91 \, \text{L} \times 77.15 \, \text{K}}{5.20 \, \text{atm} \times 293.15 \, \text{K}} \approx 0.25 \, \text{L}$.

A Balloon Filled with Helium Gas at 20 °C Occupies